Answer:
Ques 7)
{–5, –1, 3, 7, 11}
Ques 8)
3
Ques 9)
one solution.
Ques 10)
(2,-3)
Ques 11)
y= -2x+3
Step-by-step explanation:
Ques 7)
We have to find the range of the function:
f(x)=4x-1.
Given that domain is:
{-1,0,1,2,3}
The range of the function is the value of the function corresponding to the points of the domain.
so when x= -1
f(x)=4×(-1)-1=-4-1=-5
when x=0
f(x)=4×0-1=0-1=-1
when x=1
f(x)=4×1-1=4-1=3
when x=2
f(x)=4×2-1=8-1=7
when x=3
f(x)=4×3-1=12-1=11
Hence, the range of the function is:
{-5,-1,3,7,11}
Ques 8)
We have to find the slope of the graph of the equation:
Firstly we will write our equation in the slope intercept form as:
Where m is the slope of the graph and c is the y-intercept of the graph.
Hence,
Hence, the slope of the equation is:
3
Ques 9)
We have to find the number of solution of the system of equations as:
x – 2y = 2
y = –2x + 5
On solving the system of equation by substitution method:
we put second equation in first to obtain:
x-2(-2x=5)=2
x+4x-10=2
5x=2+10
5x=12
x=12/5=2.4
Also putting the value of x in second equation we obtain:
y=0.2
Hence, we obtain a unique value of x and y on solving these system of equations.
So it has only one solution.
Ques 10)
We are given system of equation as:
3x-5y=21
2x+y=1
the second equation could also be written as:
y=1-2x-----------(a)
on putting the value of y in first equation we get:
3x-5(1-2x)=21
3x-5+10x=21
13x-5=21
13x=21+5
13x=26
x=26/13=2
i.e. x=2
on putting the value of x in equation (a) we get:
y=1-2×(2)=1-4=-3
i.e. y= -3
Hence the solution is:
(2,-3)
Ques 11)
We have to convert the equation:
4x+2y=6 into slope-intercept form of the line.
We know that the slope intercept form of the line is given as:
y=mx+c
where m is the slope of the line and c is the y-intercept.
2y=-4x+6
on dividing both side of the equation by 2 we obtain:
y=-2x+3