Answer:
To determine the number of atoms of Boron that are present within 3.61 grams of Boron Trifluoride, it would be best to convert the grams to moles of the compound and then after that use the Avogadro's number to determine the number of molecules and then use the 1 to 3 ratio to determine the total number of Boron atoms.
Answer:
KOH
Explanation:
When ionic compounds (a metal and a nonmetal) dissolve, they are good conductors of electricity, and would result in the brightest light. Weak bases and covalent compounds do not dissolve, so KOH, a strong base and ionic compound, would dissolve and conduct electricity.
The number of electrons in an atom's outermost valence shell governs its bonding behaviour. Elements whose atoms have the same number of valence electrons are grouped together in the Periodic Table. ... Nonmetals tend to attract additional valence electrons to form either ionic or covalent bonds.
Considering the equation,
3Na₂SO₄(aq)+2Al(NO₃)₃(aq)------>Al₂(SO₄)₃(s)+6NaNO₃(aq)
As it can be seen from the equation,
2 moles of Al(NO₃)₃ reacts with 3 moles of Na₂SO₄ to give 1 mol of Al₂(SO₄)₃.
Here 690 mL of 2.5 M Al(NO₃)₃=2.5× 690/1000
=1.7 mol of Al(NO₃)₃
As 2 moles of Al(NO₃)₃ give 1 mol of Al₂(SO₄)₃
So 1.7 mol of Al(NO₃)₃ give 1.7/2 mol of Al₂(SO₄)₃
so it will give 0.86 mol of Al₂(SO₄)₃.
Moles=mass given /molar mass
molar mass of Al₂(SO₄)₃= 342.1509 g/mol
Moles= mass given/342.1509
0.86=mass given/342.1509
mass of Al₂(SO₄)₃=295.1 g
so 295.1 g of Al₂(SO₄)₃ will be produced.