Answer:
B. He should change the lengths of the vectors that point tangent to the circle so that each is the same length.
Explanation:
A uniform circular motion is a motion in a circle where the tangential speed of the object is constant.
In the motion map:
- The arrows pointing towards the centre of the circle represent the centripetal acceleration, and their length represent the magnitude of the acceleration
- The arrows pointing tangential to the circle represent the tangential speed, and their length represent the magnitude of the speed
In this motion map, we see that the length of the vectors pointing tangent to the circle is not constant: this means that the speed is not constant. In order to have a uniform circular motion, the speed must be constant, therefore the lengths of the vectors that point tangent to the circle must be the same.
By Newton's 2nd law of motion, F = ma, where F is force, m is mass, and a is acceleration.
Rearranging this equation to find acceleration would give us:
a = F/m
The horizontal force to the right is 10N, because the box is pushed to the right with a force of 20N, and the friction force of 10N opposes that, so:
20N - 10N = 10N
The mass is 2kg.
Putting these values into the equation gives us:
a = F/m
= 10/2
= 5ms^-2
The acceleration of the box is 5ms^-2
Simple reaction time involves selecting a
specific and correct response from several choices when presented with several
different stimuli. This is very important because historically, this was the
first indicators of intelligence pioneered by Francis Galton. To measure one’s
intelligence is to know how he quick a person could respond to the stimulus
with an already expected response wherein the stimulus is given unknown to the
receiver. In other terms, the intelligence is measured on how quick a person
could grasp certain concepts and how he could think fast and answer them
correctly.
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Weight increases but mass stays the same
Answer:
cart displacement is 66 m
Explanation:
given data
velocity = 5 m/s
acceleration = 2 m/s²
time = 6 s
to find out
What is the
magnitude of cart displacement
solution
we will apply here equation of motion to find displacement that is
s = ut + 0.5×at² .............1
here s id displacement and u is velocity and a is acceleration and time is t here
put all value in equation 1
s = ut + 0.5×at²
s = 5(6) + 0.5×(2)×6²
s = 66
so cart displacement is 66 m
