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olganol [36]
3 years ago
12

Calculate the kinetic energy in joules of an automobile weighing 2135 lb and traveling at 55 mph. (1 mile = 1.6093 km, 1 lb = 45

3.59 g)
Physics
1 answer:
victus00 [196]3 years ago
4 0
<span>Let's convert the speed to m/s: speed = (55 mph) (1609.3 m / mile) (1 hour / 3600 seconds) speed = 24.59 m/s Let's convert the mass to kilograms: mass = (2135 lb) (0.45359 kg / lb) mass = 968.4 kg We can find the kinetic energy KE: KE = (1/2) m v^2 KE = (1/2) (968.4 kg) (24.59 m/s)^2 KE = 292780 joules The kinetic energy of the automobile is 292780 joules.</span>
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Which of the following are disadvantages of solar energy?
Ronch [10]
There are a few disadvantages, so let's start with the most simple. Night time, the sun isn't up so solar panels can't gather energy. Also, when it's snowing or raining or it's cloudy. Another thing is as of right now it's costly to get solar panels installed. Furthermore, a solar panel has to be maintained as in brushed cause debris can get caught on it and therefore block the sunlight. If you have anymore questions just comment and I will help further. I hope this helps!
3 0
3 years ago
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If the work function of a material is such that red light of wavelength 700 nm just barely initiates the photoelectric effect, w
lawyer [7]

Answer: 2.13(10)^{-19} J

Explanation:

The photoelectric effect consists of the emission of electrons (electric current) that occurs when light falls on a metal surface under certain conditions.  

If the light is a stream of photons and each of them has energy, this energy is able to pull an electron out of the crystalline lattice of the metal and communicate, in addition, a kinetic energy.  

<u>This is what Einstein proposed:  </u>

Light behaves like a stream of particles called photons with an energy  E

E=h.f (1)

Where:

h=6.63(10)^{-34}J.s is the Planck constant  

f is the frequency

Now, the frequency has an inverse relation with the wavelength \lambda:  

f=\frac{c}{\lambda} (2)  

Where c=3(10)^{8}m/s is the speed of light in vacuum  and \lambda=400nm=400(10)^{-9}m is the wavelength of the absorbed photons in the photoelectric effect.

Substituting (2) in (1):

E=\frac{h.c}{\lambda} (3)

So, the energy E of the incident photon must be equal to the sum of the Work function \Phi of the metal and the maximum kinetic energy K_{max} of the photoelectron:  

E=\Phi+K_{max} (4)  

Rewriting to find K_{max}:

K_{max}=E-\Phi (5)

Where \Phi is the minimum amount of energy required to induce the photoemission of electrons from the surface of a metal, and its value depends on the metal:

\Phi=h.f_{o}=\frac{h.c}{\lambda_{o}} (6)

Being \lambda_{o}=700nm=700(10)^{-9}m the threshold wavelength (the minimum wavelength needed to initiate the photoelectric effect)

Substituting (3) and (6) in (5):  

K_{max}=\frac{h.c}{\lambda}-\frac{h.c}{\lambda_{o}}

K_{max}=h.c(\frac{1}{\lambda}-\frac{1}{\lambda_{o}}) (7)

Substituting the known values:

K_{max}=(6.63(10)^{-34}J.s)(3(10)^{8}m/s)(\frac{1}{400(10)^{-9}m}-\frac{1}{700(10)^{-9}m})

K_{max}=2.13(10)^{-19} J >>>>>This is the maximum kinetic energy that ejected electrons must have when violet light illuminates the material

7 0
4 years ago
A quarter-wave monopole radio antenna (also called a Marconi antenna) consists of a long conductor of one quarter the length of
alexandr402 [8]

Answer:

145.91 m

Explanation:

Data provided in the the question:

Wavelength of radio wave, \lambda = \frac c f

Here, c is speed of radio wave in air = 3 × 10⁸ m/s

f is the frequency = 514 kHz = 514 × 10³ Hz

Thus,

Wavelength = (3 × 10⁸) ÷ (514 × 10³) m

or

Wavelength = 583.65 m

Thus,

The height of the antenna will be

= \frac \lambda  4 = 583.65 ÷ 4 m

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3 0
3 years ago
A skateboarder starts up a 1.0-m-high, 30° ramp at a speed of 7.6 m/s . The skateboard wheels roll without friction. At the top,
andriy [413]

Answer:

t = 1.084 s

s = 8.25 m

Explanation:

given,

height from where skate board start (h) = 1 m

speed = 7.6 m/s

we know

v² = u² + 2 g h                      

v² =7.6² + 2×9.81× 1

v = 8.79 m/s                        

v_y = v sin \theta

v_y =8.79\times sin 30^0

v_y = 4.39 m/s

s = s_o + v_y \times t +\dfrac{1}{2}at^2

0 = 1 + 4.39 \times t - 4.9 t^2

t = 1.084 s

then horizontal distance

s =v_x \times t

s = 8.79 \times cos 30^0 \times 1.084

s = 8.25 m

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Answer:

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