Calculate the kinetic energy in joules of an automobile weighing 2135 lb and traveling at 55 mph. (1 mile = 1.6093 km, 1 lb = 45
1 answer:
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Answer:
t = 123.59s
Explanation:
For the launch pad section:
Vf = Vo + a*t where Vo=0.
Vf = 35*25 = 875m/s
The distance traveled during the launch:
Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.
where d= 10937.5m; Vo=875m/s.
Solving for t:
t1 = -11.093s t2 = 98.59s
So, the total time of flight will be:
Answer:
part (a) v = 1.7 m/s towards right direction
part (b) Not an elastic collision
part (c) F = -228.6 N towards left.
Explanation:
Given,
- Mass of the first puck =
- Mass of the second puck =
- initial velocity of the first puck =
- Initial velocity of the second puck =
Part (a)
Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.
From the conservation of linear momentum,
Direction of the velocity is towards right due to positive velocity.
part (b)
Given,
Final velocity of the second puck =
Let be the final velocity of first puck after the collision.
From the conservation of linear momentum,
For elastic collision, the coefficient of restitution should be 1.
From the equation of the restitution,
Therefore the collision is not elastic collision.
part (c)
Given,
Time of impact = t =
we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,
Negative sign indicates that the force is towards in the left side of the movement of the first puck.
Since the biker is moving at constant speed
so we will have
here we know that
time = 4 second
now we have
now at the top point it feels free fall
so it is
so height of the bike at the top is same as diameter
Yes it will hurt on falling from this height