All categories

2 years ago

How does mass influence the kinetic energy and the potential energy of an object?

Physics

2 answers:

vladimir2022 [97]2 years ago

8 0

Answer:

The faster an object moves, the more kinetic energy it has. The more mass an object has, the more kinetic energy it has.

Explanation:

Alinara [238K]2 years ago

8 0

Answer:

Explanation:

KE = mv²/2 or (1/2)mv²

so assume v = 2 and m = 3 then the KE would be 6. Now assume v = 2 and m = 2 then KE would be 4, so the KE increases if the mass increases and velocity is constant.

PE = mgh

g = 10 assume h = 10 and m = 10

then PE = 1000

now g = 10 h = 10 but m = 5

then PE = 500 so, if m decreases, pe also decreases

You might be interested in

A rope of length L has circular cross-sectional area A and density rho = m/V , where m is the mass of the rope and V = A · L is

hram777 [196]

Answer: µ = ρ¹ * A¹

Where x=1 and y=1

Explanation: According to the question, the mass per unit length (µ) is related to the density (ρ) and area A are related by the formulae below

µ = ρ * A

The dimension for each of these quantities is given below

Since µ is mass per unit length, unit is Kg/m and the dimension is ML^-1

ρ is density with unit kg/m³ and the dimension is ML^3

A is area with unit m², thus the dimension is M^2

Note that using dimensional analysis means we will be using the 3 fundamental quantities (mass, length and time) in our analysis.

Their dimensions below

Mass = M

Length = L

Time = T

Since the mass per unit length is related to density and area, we have a mathematical equation to provide a solution as shown below

µ = ρ^x * A^y.

By getting the power of x and y we will be able to get the formula that relates the quantities.

This is done by slotting in the dimensions of the respective quantities.

ML^-1 = (ML^-3)^x * (L²) ^y

By using law of indices on the right hand side of the equation, we have that

ML^-1 = (M^x * L^-3x) * (L^2y)

Also applying law of indices on the right hand side, we have that

ML^-1 = (M^x) * (L^-3x +2y)

The next step is to relate equal variables on both sides

For the M variable

M¹ = M^x which results to

x = 1

For the L variable

L^-1 = L^-3x+2y which results to

-1 = - 3x +2y

But x = 1

We have that

-1 = - 3(1) +2y

-1 = - 3 + 2y

-1 +3= 2y

2 = 2y

y = 1

Thus x=1 and y=1 and the formulae that relates the quantities is

µ = ρ¹ * A¹

3 0

3 years ago

A 3.0 m tall, 40 cm diameter concrete column supports a 235,000 kg load. by how much is the column compressed? assume young's mo

statuscvo [17]

The Young modulus E is given by:
$E= \frac{F L_0}{A \Delta L}$
where
F is the force applied
A is the cross-sectional area perpendicular to the force applied
$L_0$ is the initial length of the object
$\Delta L$ is the increase (or decrease) in length of the object.

In our problem, $L_0 = 3.0 m$ is the initial length of the column, $E=3.0 \cdot 10^{10}N/m^2$ is the Young modulus. We can find the cross-sectional area by using the diameter of the column. In fact, its radius is:
$r= \frac{d}{2}= \frac{40 cm}{2}=20 cm=0.2 m$
and the cross-sectional area is
$A=\pi r^2 = \pi (0.20 m)^2=0.126 m^2$
The force applied to the column is the weight of the load:
$W=mg=(235000 kg)(9.81 m/s^2)=2.305 \cdot 10^6 N$

Now we have everything to calculate the compression of the column:
$\Delta L = \frac{F L_0}{EA}= \frac{(2.305\cdot 10^6 N)(3.0 m)}{(3.0\cdot 10^{10}N/m^2)(0.126 m^2)} =1.83\cdot 10^{-3}m$
So, the column compresses by 1.83 millimeters.

3 0

3 years ago

Read 2 more answers

The current estimate for the age of earth of 4.57 ga comes from _____.

Whitepunk [10]

The estimation of the age of the Earth comes from scientists who studied the rock formation under the Earth's crust. They believe that during the Big Bang, the Earth, together with the other celestial bodies in the universe, were formed. Under the Earth's soil contain radioactive materials that have known decay rates. Using these rate, they undergo tests like rock dating to find the time of its existence.

4 0

3 years ago

Two bullets are fired simultaneously parallel to a horizontal plane. The bullets have different masses and different initial vel

Ksivusya [100]

Answer:

Therefore, the answer is E. They strike the plane at the same time.

Explanation:

Here, it is seen that the time depends only on acceleration due to gravity (which is a constant) and vertical displacement, and not on velocity of the bullets or mass of the bullets.

Hence, the bullets that are fired simultaneously parallel to the horizontal plane will strike the plane at the same time.

using equation of motion for displacement

s= ut + ¹/₂gt²

here, g is the acceleration due to gravity along y- direction

U along y is 0

s = (0)t + ¹/₂gt²

s=¹/₂gt²

make t the subject of formula = $\sqrt{\frac{2s}{g} }$

6 0

3 years ago

Consider the substance represented by the heating curve. What is the MOST accurate conclusion can you draw about the vaporizatio

tino4ka555 [31]

The answer is D. it requires much more energy

4 0

3 years ago