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2 years ago

6

How does mass influence the kinetic energy and the potential energy of an object?

2 answers:

vladimir2022 [97]2 years ago

8 0

Answer:

The faster an object moves, the more kinetic energy it has. The more mass an object has, the more kinetic energy it has.

Explanation:

Alinara [238K]2 years ago

8 0

Answer:

Explanation:

KE = mv²/2 or (1/2)mv²

so assume v = 2 and m = 3 then the KE would be 6. Now assume v = 2 and m = 2 then KE would be 4, so the KE increases if the mass increases and velocity is constant.

PE = mgh

g = 10 assume h = 10 and m = 10

then PE = 1000

now g = 10 h = 10 but m = 5

then PE = 500 so, if m decreases, pe also decreases

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3 years ago

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Calculate the wavelength in centimeters of radar energy at a frequency of 10 GHz. What is the frequency in gigahertz of radar en

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Explanation:

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2 years ago

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2 years ago

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A car travels a distance of 200m in 20s. The engine of the car provides a driving force of 1000N. What is the power output of th

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3 years ago

Astronauts on the first trip to Mars take along a pendulumthat has a period on earth of 1.50 {\rm s}. The period on Mars turns o

svetlana [45]

Answer:

3.7 m/s^2

Explanation:

The period of a simple pendulum is given by:

$T=2 \pi \sqrt{\frac{L}{g}}$

where L is the length of the pendulum and g is the free-fall acceleration on the planet.

Calling L the length of the pendulum, we know that:

$T_e = 2 \pi \sqrt{\frac{L}{g_e}}=1.50 s$ is the period of the pendulum on Earth, and $g_e = 9.8 m/s^2$ is the free-fall acceleration on Earth

$T_m = 2 \pi \sqrt{\frac{L}{g_m}}=2.45 s$ is the period of the pendulum on Mars, and $g_m = ?$ is the free-fall acceleration on Mars

Dividing the two expressions we get

$\frac{T_e}{T_m}=\sqrt{\frac{g_m}{g_e}}$

And re-arranging it we can find the value of the free-fall acceleration on Mars:

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3 years ago