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3 years ago

How does mass influence the kinetic energy and the potential energy of an object?

Physics

2 answers:

vladimir2022 [97]3 years ago

8 0

Answer:

The faster an object moves, the more kinetic energy it has. The more mass an object has, the more kinetic energy it has.

Explanation:

Alinara [238K]3 years ago

8 0

Answer:

Explanation:

KE = mv²/2 or (1/2)mv²

so assume v = 2 and m = 3 then the KE would be 6. Now assume v = 2 and m = 2 then KE would be 4, so the KE increases if the mass increases and velocity is constant.

PE = mgh

g = 10 assume h = 10 and m = 10

then PE = 1000

now g = 10 h = 10 but m = 5

then PE = 500 so, if m decreases, pe also decreases

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Option C would be the right one

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Is the heart. And this should be in Biology not Physics.

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3 years ago

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A Cessna 150 aircraft has a lift-off speed of approximately 125 km/h. What minimum constant acceleration does this require if th

aivan3 [116]

Answer:

Part a)

$a = 3.65 m/s^2$

Part b)

$t = 9.5 s$

Part c)

$v_f = 55.1 m/s$

Explanation:

Part a)

As we know that it starts from rest and moves on runway by total distance 165 m

so we will have

$v_f^2 - v_i^2 = 2ad$

$v_f^2 - 0 = 2(a)(165)$

$v_f = 125 km/h = 34.7 m/s$

now we have

$a = 3.65 m/s^2$

Part b)

Now for take off time we will have

$v_f - v_i = at$

$34.7 - 0 = 3.65 t$

$t = 9.5 s$

Part c)

$v_f = v_i + at$

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7 0

3 years ago

450 nm of light falls on a single slit of width 0.30 mm. What is the angular width of the central diffraction peak

Andre45 [30]

Angular width is 3 x 10^-3

Let D be the distance between source and screed d the distance between coherent source then for central diffraction maxima,

where λ is wavelength

Given:

λ = 450 nm = 450×10^−9m

d = 0.3x10^−3m, D = 1m

W = 2 x 450×10^−9/0.3x10^−3*1

To Find:

Angular width

Solution: The width of the central maxima is nothing but the difference between the positions of the first two minima. Hence we will use the expression for the position of minima and accordingly obtain the expression of the width of central maxima and secondary maxima

θ = W/D

θ = 2 x 450×10^−9/0.3x10^−3*1/1 = 3 x 10^-3

Hence, angular width is 3 x 10^-3

Learn more about Angular width here:

brainly.com/question/25292087

#SPJ4

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2 years ago

jake drags a sled of mass 10 kg across the snow. the sled is attached to a rope that he pulls with a force of 30 n at an angle o

bagirrra123 [75]

Answer:

The normal force is 85,42 N

Explanation:

There is no friction force, therefore there is no relationship between the normal force and the friction.

We can find the normal force using a free body diagram and check the forces that are acting on the sled. The total forces are equal to 0 because there is no movement in the y-axis. The movement exists only on the x-axis.

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4 years ago

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