Within visible light, violet has the lowest frequency. a. True b. False
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To solve this problem it is necessary to apply the second derivative of the function to find the maximum time reference and thus calculate the maximum voltage.
With the maximum voltage by Ohm's Law it is possible to find the maximum current.
Ohm's law defines that
E = I*R
Where,
I = Current
R= Resistance
On the other hand by faraday studies and the potential can be expressed at the rate of change of the electric flow, that is
Replacing with our values we have that
The second derivative is
When E' = 0 we have a Maximum, then
0 = -36t+36
t = 1
Therefore when the time is 1s E has a Maximum, replacing at the function
Then the maximum current will be given by
Therefore the maximum current induced in the ring is 6.42A