An 850.0 kg car wants to accelerate from rest to a speed of 18.0 m/s.
1 answer:
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Answer:
It increases proportionally
Explanation:
The gravitational force between the Earth and an object on its surface is given by
where
G is the gravitational constant
M is the Earth's mass
m is the mass of the object
R is the Earth's radius
In this problem, the Earth's mass is increased, while the diameter (and therefore, the radius) doesn't change. From the equation, we see that the gravitational force is directly proportional to the Earth's mass: therefore, if the mass is increased, the force will increase as well by the same proportion (for example, if the mass is doubled, the force will double as well)
By using Ohm's law, we can find what should be the resistance of the wire, R:
Then, let's find the cross-sectional area of the wire. Its radius is half the diameter,
So the area is
And by using the resistivity of the Aluminum,
, we can use the relationship between resistance R and resistivity:
to find L, the length of the wire:
Then, let's find the cross-sectional area of the wire. Its radius is half the diameter,
So the area is
And by using the resistivity of the Aluminum,
to find L, the length of the wire:
2.57 joule energy lose in the bounce .
<u>Explanation</u>:
when ball is the height of 1.37 m from the ground it has some gravitational potential energy with respect to hits the ground
Formula for gravitational potential energy given by
Potential Energy = mgh
Where ,
m = mass
g = acceleration due to gravity
h = height
Potential energy when ball hits the ground
m= 0.375 kg
h = 1.37 m
g = 9.8 m/s²
Potential Energy = 5.03 joule
Potential energy when ball bounces up again
h= 0.67 m
Potential Energy = 2.46 joule
Energy loss = 5.03 - 2.46 = 2.57 joule
2.57 joule energy lose in the bounce