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Oksana_A [137]
3 years ago
8

A chemist test new mixtures for paint samples and decides one mixtuees stickiness makes is worthless

Chemistry
1 answer:
monitta3 years ago
4 0

Answer:

known are those proposed by Patrick,1 and Howard,2 and the group scheme devised by ... are unsatisfactory for complicated food mixtures and entirely useless so far as ... Congdon's procedure is evidently based on qualitative tests made on the ... it was decided at the outset that on account of the complex food mixtures.

Explanation:

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Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili
Katen [24]

<u>Answer:</u> The value of equilibrium constant for the given reaction is 56.61

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}

\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M

\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

                         H_2+I_2\rightleftharpoons 2HI

<u>Initial:</u>                0.1    0.1

<u>At eqllm:</u>          0.1-x   0.1-x   2x

Evaluating the value of 'x'

\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M

The expression of K_c for above equation follows:

K_c=\frac{[HI]^2}{[H_2][I_2]}

[HI]_{eq}=2x=(2\times 0.079)=0.158M

[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M

[I_2]_{eq}=0.0210M

Putting values in above expression, we get:

K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0
3 years ago
I really need help it's urgent help ! Don't ignore it .Your work will be appreciated and don't spam
gtnhenbr [62]

ツ here your answer

\huge\red{ \mid{\fbox{\tt{answer}}\mid}}

  • A)Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s)

  • 2KBr(aq)+BaI2(aq) → 2KI(aq)+BaBr2(s)

  • B)Balance the Chemical Equation for the reaction of calcium carbonate with hydrochloric acid: 
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<em><u>M</u></em><em><u>a</u></em><em><u>r</u></em><em><u>k</u></em><em><u> </u></em><em><u>m</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>b</u></em><em><u>r</u></em><em><u>a</u></em><em><u>i</u></em><em><u>n</u></em><em><u>l</u></em><em><u>i</u></em><em><u>s</u></em><em><u>t</u></em>

8 0
2 years ago
Is sublimation exothermic or endothermic
Masja [62]

Answer:

endormic

Explanation:

It occurs at a temperature and pressures below a substance's triple point on its phase diagram, which corresponds to the lowest pressure at which the substance can exist as a liquid

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2 years ago
How can you remove salt from oil
Gennadij [26K]

Answer:

you can't

Explanation:

4 0
2 years ago
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This element is found in group 1, period 7 and has the lowest mass in this period. *
liraira [26]

The answer is Francium.

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3 years ago
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