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Oksana_A [137]
3 years ago
8

A chemist test new mixtures for paint samples and decides one mixtuees stickiness makes is worthless

Chemistry
1 answer:
monitta3 years ago
4 0

Answer:

known are those proposed by Patrick,1 and Howard,2 and the group scheme devised by ... are unsatisfactory for complicated food mixtures and entirely useless so far as ... Congdon's procedure is evidently based on qualitative tests made on the ... it was decided at the outset that on account of the complex food mixtures.

Explanation:

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Help plzzzzz ASAP!!!!!!!!
SIZIF [17.4K]

1. NaF, Na₂S, Na₃P, Na₂O

2. MgF₂, MgS, Mg₃P₂, MgO

3. AlF₃, Al₂S₃, AlP, Al₂O₃

<h3>Further explanation</h3>

Given

Ionic charge

Required

The formula of binary ionic compounds

Solution

Ionic compounds consisting of cations (ions +) and anions (ions -)

Ionic compounds usually consist of metal cations and non-metal anions

Metal: cation, positively charged.

Nonmetal: negatively charged

The anion cation's charge is crossed

The ionic compounds :

1. NaF, Na₂S, Na₃P, Na₂O

2. MgF₂, MgS, Mg₃P₂, MgO

3. AlF₃, Al₂S₃, AlP, Al₂O₃

4 0
2 years ago
100 POINTS !!!! TO RIGHT AWNSER!!!
Alecsey [184]
The answer is going to be C) because 
A)We know that she put all three boxes in the window and let them sat their for a hour
B)We know that the boxes are the same size
C)She used three different materials,and she wants to measure the warmth of each box. To see which one is the warmest 
D)She never said anything about mass
Hopes This Helps:)
3 0
3 years ago
Read 2 more answers
What is the frequency of an electromagnetic wave that has a wavelength of
Korolek [52]

➡ ANSWER

☑ <em><u>C</u></em><em><u>.</u></em><em><u> </u></em><em><u>3.5 105</u></em><em><u> </u></em><em><u>Hz</u></em>

3 0
2 years ago
Five solutions on how to prevent air pollution ​
I am Lyosha [343]

Answer:

Reduce number of trips

Avoid burning leaves

Avoid using garden equipments

Reduce the use of wood stove

Avoid gas-powered lawn.

Explanation:

7 0
3 years ago
g Phosphorus -32 is a commonly used radioactive nuclide in biochemical research, particularly in studies of nucleic acids. The h
Setler79 [48]

Answer:

6.88 mg

Explanation:

Step 1: Calculate the mass of ³²P in 175 mg of Na₃³²PO₄

The mass ratio of Na₃³²PO₄ to ³²P is 148.91:31.97.

175 mg g Na₃³²PO₄ × 31.97 g ³²P/148.91 g Na₃³²PO₄ = 37.6 mg ³²P

Step 2: Calculate the rate constant for the decay of ³²P

The half-life (t1/2) is 14.3 days. We can calculate k using the following expression.

k = ln2/ t1/2 = ln2 / 14.3 d = 0.0485 d⁻¹

Step 3: Calculate the amount of P, given the initial amount (P₀) is 37.6 mg and the time elapsed (t) is 35.0 days

For first-order kinetics, we will use the following expression.

ln P = ln P₀ - k × t

ln P = ln 37.6 mg - 0.0485 d⁻¹ × 35.0 d

P = 6.88 mg

3 0
2 years ago
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