The applicable equation:
P = F/A
P = pressure
F = Force or weight
A = surface area
Pressure on each cylinder = (W/n)/A
Where n = number of cylinders. Additionally, pressure in the reservoir is equivalent to the pressure in each cylinder.
Net pressure = 75 - 14.7 = 60.3 psi
Therefore,
60.3 = (W/n)/A = (450/n)/(πD^2/4) = (450/n)/(π*1.5^2/4) = (450/n)/(1.7671)
60.3*1.7671 = 450/n
106.03 = 450/n
n = 450/106.3 = 4.244 ≈ 5
The number of cylinders is 5.
I believe the correct answer is true. <span>A machine can make doing work easier by reducing the force exerted, changing the distance over which the force is exerted, or changing the direction of the force. Hope this answer the question.</span>
Answer:
3: High and low tides
Explanation:
Tides can be defined as the rise and fall of water level in water bodies such as lakes and oceans due to the gravitational force of attraction exerted by the moon on earth. The side closest to the moon creates a bulge of water known as high tide. Low tides are generally experienced when a sea level is not within the bulge.
Additionally, they are caused by the cycle of rising and falling ocean water that are repeated approximately every 12.5 hours.
In conclusion, the gravitational pull of the Moon is responsible for visible changes on the surface of Earth. Thus, the pull of the Moon's gravity causes high and low tides on planet Earth's surface.
Answer:
Answered
Explanation:
A separated flow is a characteristic of a flow-field over a __Stalled__ airfoil. Stall is the reduction in lift coefficient generated by a foil as angle of attack increases.
The critical angle of attack is typically about 15 degrees, but it may vary significantly depending on the fluid, foil, and Reynolds number.The boundary layer will tend to separate from the top surface and a large wake is formed downstream.
Answer:
Explanation:
a )
Depth of hole from surface of water d = .50 m - .03 m = .47 m
velocity of efflux v = √ 2gd
v = √ (2 x 9.8 x .47 )
v = 3.03 m /s
b )
Volume flow rate = π R² v where R is radius of hole at the bottom .
= 3.14 x ( .005 ) ² x 3.03 m/s
= 2.378 x 10⁻⁴ m³ /s
c )
Volume of water collected in 60 s
= 2.378 x 10⁻⁴ x 60
= 1.4268 x 10⁻² m³
If height attained in collecting container be h
π R² h = 1.4268 x 10⁻² m³ where R is radius of container
3.14 x ( .1 )² x h = 1.4268 x 10⁻²
h = .4544 m .
Pressure at the bottom of container = hρ g
where h is height of water , ρ is density of water
Pressure = .4544 x 1000 x 9.8 N /m²
= 4453.12 N /m²