First aid suggestions include:
Hold your face under running water for 15 to 20 minutes and allow the water stream to flood into your eyes. Use your fingers to hold your eyelids apart (make sure there is no trace of the chemical on your fingers).
If you wear contact lenses, remove them as soon as possible.
Seek immediate medical advice. Medical staff will need to know what chemical was involved, particularly whether it was acid or alkaline, liquid or powder.
Do not judge the seriousness of your eye injury on the degree of pain. For example, alkali chemicals don’t usually cause significant symptoms, but can seriously damage the eye.
Powder or particulate (granular matter, like wet concrete) chemicals can be particularly damaging since they are more difficult to flush out.
Answer:
Option B. 2.8 s
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 27 m/s
Angle of projection (θ) = 30
Acceleration due to gravity (g) = 9.8 m/s²
Time of flight (T) =?
The time of flight of the ball can be obtained as follow:
T = 2uSineθ / g
T = 2 × 27 × Sine 30 / 9.8
T = 2 × 27 × 0.5 / 9.8
T = 27 / 9.8
T = 2.8 s
Therefore, time of flight of the ball is 2.8 s
We define acceleration as the rate of change of the velocity
Thus, if you have positive velocity and positive acceleration, your <u>speed increases.</u>
If you have positive velocity and negative acceleration, your speed decreases.
Now you get the idea, we will see that the correct option is graph 1.
We know that the car moves towards the right (let's define this as "the car has positive velocity") and we also know that te car is slowing down constantly (thus the acceleration needs to be negative and constant).
By looking at the graphs, the only one with these properties is graph 1.
If you want to learn more, you can read:
brainly.com/question/12550364
Answer:
A. pulls back on the Earth, which is the main cause of the rise and fall of the ocean tides on Earth.
Any charged object can<span> exert the force upon other objects ... i think tell me if im right</span>
