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luda_lava [24]
4 years ago
15

A 12 A fuse is placed in a parallel circuit that has two branches. 8 A flows in branch 1 and 6 A flows in branch 2. This fuse

Physics
1 answer:
kaheart [24]4 years ago
3 0

Answer:

1. will blow because the total current in this circuit is 14 A which is greater than 12 A.

Explanation:

According to Kirchoff current law (KCL) which states that the total current flowing in a circuit is equal to the sum of the individual branch current.

If the supply current is greater than the sum of the individual branch current, then the load will collapse or blow off.

In the question given, the total current of the fuse is 12A

Sum of branch currents = current in branch 1 + current in branch 2

= 8A+6A

= 14A

As we can see that the supply current is lower than the sum of the branch current, this will cause the fuse to blow because some of the branch current will be sent back on the fuse and thereby causing the fuse to blow.

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g The electric field in a sinusoidal wave changes as E =125 N>C2cos 311.2 * 1011 rad>s2t +14.2 * 102 rad>m2x] (a) In wh
Elan Coil [88]

Answer:

a) the propagation direction is x, b)   E₀ = 125 N / C² , c) B = 41.67 10⁻⁸ T ,

d)  f = 4.95 10¹¹ Hz, e)  λ = 4.42 10⁻³ m, f) the speed of light ,

Explanation:

The equation they give for the sine wave is

      E = 125 cos (14.2 10² x - 311.2 10¹¹ t)

This expression must have the general shape of a traveling wave

      E = Eo cos (kx - wt + Ф)

we can equal each term between the two equations

a) the propagation direction is x, since it is the term that accompanies the vector k

b) the amplitude is the coefficient before the cosine function

          E₀ = 125 N / C²

c) to find the amplitude of the magnetic field we use that the two fields are in phase

          C = E / B

          B = E / c

          B = 125/3 10⁸

          B = 41.67 10⁻⁸ T

d) the angular velocity is

          w = 311.2 10¹¹ rad / s

angular velocity and frequencies are related

          w = 2π f

           f = w / 2π

           f = 311.2 10¹¹ / 2π

           f = 4.95 10¹¹ Hz

e) the wavelength is obtained from the wave number

          k = 2π /λ

          k = 14.2 10² rad / m

          λ = 2π / k

          λ = 2π / 14.2 10²

          λ = 4.42 10⁻³ m

f) the speed of an electromagnetic wave is the speed of light

g) what is a transverse wave

4 0
3 years ago
During a sunny afternoon, the sun suddenly seems much less bright than usual. The daylight seems much less intense, as if there
Tatiana [17]

Answer:

D). A sudden change in temperature increased the density of the atmosphere.

Explanation:

The claim that can be made and supported with evidence regarding the temporary decrease in light would be 'a sudden change in temperature will increase the density of the atmosphere.' <u>As the temperature increases, the molecules in the atmosphere begin to move fastly which causes a decrease in atmosphere density while it increases with the fall in temperature. As a result, the intensity of sunlight gets affected due to molecules being heavier and floating in the atmosphere</u>. Thus, <u>option D</u> is the correct answer.

8 0
3 years ago
3) Ęplain why muddy water is<br> Heterogeneous<br> mixture
nataly862011 [7]

Answer:

muddy water is a heterogeneous mixture, which is Suspension.

7 0
3 years ago
An electric current heats a 221 g (0.221 kg) copper wire from 20.0 °C to 38.0 °C. How much heat was generated by the current?
lorasvet [3.4K]

Answer:

Heat generated by the current = 1547.89 J

Explanation:

We have equation for heat energy H = mCΔT

Mass of copper = 0.221 kg

Specific heat of copper = 0.093 kcal/kgC° = 389.112 J/kgC°

ΔT = 38 - 20 = 18°C

Substituting in H = mCΔT

           H = 0.221 x 389.112 x 18 = 1547.89 J

Heat generated by the current = 1547.89 J

     

3 0
4 years ago
An automobile with a mass of 1240.00 kg has 3.99 m between
Vitek1552 [10]

Answer:

948.15248\ N

5134.04751\ N

Explanation:

F_f = Force on front wheels

F_r = Force on rear wheels

Distance between CG and rear wheel = 3.99-0.622 = 3.368 m

F_r=1240\times 9.81-F_f

As the forces are conserved we have

(1240\times 9.81-F_f)3.368=F_f\times 0.622\\\Rightarrow 12164.4-F_f=\dfrac{0.622F_f}{3.368}\\\Rightarrow 12164.4-F_f=0.18467F_f\\\Rightarrow F_f=\dfrac{12164.4}{1.18467}\\\Rightarrow F_f=10268.09503\ N

On rear wheels

F_r=1240\times 9.81-10268.09503\\\Rightarrow F_r=1896.30497\ N

The force on each rear whees is \dfrac{1896.30497}{2}=948.15248\ N

Force on each front wheel is \dfrac{10268.09503}{2}=5134.04751\ N

8 0
3 years ago
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