The length of a rectangle is one more than five times its width. If the perimeter is 38, find the dimensions.

1 answer:

7 0

Hello :
let : y The length and x the width .... <span>the perimeter is : 2(x+y)
</span><span>The length of a rectangle is one more than five times its width: y = x +5
</span>the system is: 2(x+y) = 38.....(1)
y = x + 5.........(2)
subst in (1) : 2(x+x+5) = 38
4x+10 = 38
4x =28...... x = 7
but: y = x +5
y = 7+5 = 12

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