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3 years ago

14

A car has a mass of 1000 km kilometers. The weight of the car is blank newtons use G equals 9.8 in KG for gravity? Help mehhhhh

please!

1 answer:

Schach [20]3 years ago

5 0

The weight of the car in the picture of the computer screen is 9,800 Newton's.

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There are 6 atoms of oxygen in Ca (NO3)2.

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17. A household installs solar panels and captures more energy than it consumes. However, their peak energ

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____________ is the unit that measures the pressure or force that pushes the flow of electrons forward through a conductor.

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Volt is the unit that measures the pressure or force that pushes the flow of electrons forward through a conductor.

When there is a circuit having a cell / battery , that cell/battery forms an electric field due to difference in voltages , and set a voltage of value equals to the difference in the voltage of two end of that cell/ battery . Because of which a electric field got set up in the conductor , which pushes electron to move inside the conductor . Unit of voltage is volt .

VOLT - A unit of electrical pressure (or electromotive force) which causes current to flow in a circuit. One volt is the amount of pressure required to cause one ampere of current to flow against one ohm of resistance. VOLTAGE - That force which is generated to cause current to flow in an electrical circuit.

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2 years ago

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How do the densities of the jovian and terrestrial planets compare?

timofeeve [1]

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The jovian density is $1.33~g/cm^3$ , while the density of terrestrial planets is much higher. For instance, the earth's density is $5.51~g/cm^3$ . The reason of this difference is in the different chemical composition: while jupiter is made of gas (mainly hydrogen), with lower density, while the terrestrial planets are made of solid and liquid, with compounds of higher density.

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3 years ago

A circular coil 17.7 cm in diameter and containing 18 loops lies flat on the gound. The Earth's magnetic field at this location

iren [92.7K]

Answer:

Explanation:

Diameter of the circular coil d = 17.7 cm = 0.177m

Current in the coil, I = 7.4 A

Number of loops in the coil, N = 18

Magnetic field, B = 5.5 x 10-5 T

Angle below line, (θ) = 66°

Write the expression for the torque in the coil

Torque = N x I x B x A x sin (θ)

Where A is the area of the coil and θ° is the angle between the magnetic field and the coil face.

The cross- sectional area of the coil = (pie)(d/2)²

A = (π)(0.177/2)² = 0.0246 m²

The Earth’s magnetic field points into the earth at an angle 66 below the line. The line points towards the north

Hence to find the angle between the magnetic field and the coil face we need to subtract the given angle by 90°

Theta = 90 – 66 = 24°

Substitute the value to find out torque

Torque = 18 x 7.4 x 5.5 x 10⁻⁵ x 0.0246 x sin(24) = 7.33 x 10⁻⁵ N-m

The torque on the coil is 7.33 x 10⁻⁵ N-m

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3 years ago