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timofeeve [1]
2 years ago
9

Guys can someone help me

Physics
1 answer:
tensa zangetsu [6.8K]2 years ago
4 0

your answer will be B . becasue light can be transformed into heat .

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how does the number of chromosomes in a persons sex compare with the number of chromosome in the body cell
koban [17]

no it doesn't why because I think that it is not the same but different.

4 0
3 years ago
What type of motion occurs when an object spins around an axis without altering its linear position?
myrzilka [38]
<h2><em>C. translational motion</em></h2><h2><em>HOPE IT HELPS !!!!!</em></h2>
8 0
2 years ago
A force of 20. Newtons to the left exerted on a cart for 10. Seconds. For what period of time must a 50.-newton force to the rig
FinnZ [79.3K]
Impulse = (force) x (time)

The first impulse was (20 N) x (10 sec) = 200 meters/sec

The second one is (50 N) x (time) and we want it equal to the first one, so

(50 N) x (time) = 200 meters/sec

Divide each side by 50N :    Time = 200/50 = <em>4 seconds</em>

By the way, the quantity we're playing with here is the cart's <em>momentum</em>.
6 0
3 years ago
If a light is moved twice (2x) as far from a surface, the area the light covers is ___ as big.
Ksenya-84 [330]

Answer:

twice

Explanation:

From magnification = height of image / height of object

Distance of image/ distance of object = magnification

If the distance and height of the object represents the initial light distance and the exposed surface respectively.

And similarly the distance and height of the image represents the final light distance and the exposed surface respectively.

Hence the new image exposure would be twice as large.

If we use the formula our point of investigation is Height of image,

H2= D2/D1× H1

H2 = 2D2/D1 × H1

H2 = 2H1

6 0
3 years ago
1. An object on Earth and the same object on the Moon would have a difference in
Feliz [49]

Answers: (1) a. weight, (2)b. Force changes by 2/9, (3)b. movement, (4)a. 40,000 Joules, (5)c. the soil will be 5°C.

<h2>Answer 1: a. weight</h2>

Mass and weight are very different concepts.  

Mass is the amount of matter that exists in a body, which only depends on the quantity and type of particles within it. This means mass is an intrinsic property of each body and remains the same regardless of where the body is located.  

On the other hand, weight is a measure of the gravitational force acting on an object and is directly proportional to the product of the mass m of the body by the acceleration of gravity g:  

W=m.g  

Then, since the Earth and the Moon have different values ​​of gravity, t<u>he weight of an object in each place will vary</u>, but its mass will not.

<h2>Answer 2: b. Force changes by 2/9</h2>

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:  

F=G\frac{m_{1}m_{2}}{r^2} (1)

Where:  

F is the module of the force exerted between both bodies  

G is the universal gravitation constant

m_{1} and m_{2} are the masses of both bodies.

r is the distance between both bodies

If we double the mass of one object (for example 2m_{1}) and triple the distance between both (for example 3r). The equation (1) will be rewritten as:

F=G\frac{2m_{1}m_{2}}{(3r)^2} (2)

F=\frac{2}{9}G\frac{m_{1}m_{2}}{r^2} (3)

If we compare (1) and (2) we will be able to see the force changes by 2/9.

<h2>Answer 3: b. movement</h2>

The Work W done by a Force F refers to the release of potential energy from a body that is <u>moved</u> by the application of that force to overcome a resistance along a path.  

When the applied force is constant and <u>the direction of the force and the direction of the movement are parallel,</u> the equation to calculate it is:  

W=(F)(d)

Now, <u>when they are not parallel, both directions form an angle</u>, let's call it \alpha. In that case the expression to calculate the Work is:  

W=Fdcos{\alpha}

Therefore, pushing on a rock accomplishes no work unless there is movement (independently of the fact that movement is parallel to the applied force or not).

<h2>Answer 4: a. 40,000 Joules</h2>

The Kinetic Energy is given by:

K=\frac{1}{2}mV^{2}   (4)

Where m is the mass of the body and V its velocity

For the first case (kinetic energy K_{1}=10000J  for a car at V_{1}=30 mph=13.4112m/s):

K_{1}=\frac{1}{2}mV_{1}^{2}   (5)

Finding m:

m=\frac{2K_{1}}{V_{1}^{2}}   (6)

m=\frac{2(10000J)}{(13.4112m/s)^{2}}   (7)

m=111.197kg   (8)

For the second case (unknown kinetic energy K_{2}  for a car with the same mass at V_{2}=60 mph=26.8224m/s):

K_{2}=\frac{1}{2}mV_{2}^{2}   (9)

K_{2}=\frac{1}{2}(111.197kg)(26.8224m/s)^{2}   (10)

K_{2}=40000J   (11)

<h2>Answer 5: c. the soil will be 5°C</h2>

The formula to calculate the amount of calories Q is:

Q=m. c. \Delta T   (12)

Where:

m  is the mass

c  is the specific heat of the element. For water is c_{w}=1 kcal/g\°C  and for soil is c_{s}=0.20 kcal/g\°C  

\Delta T  is the variation in temperature (the amount we want to find for both elements)

This means we have to clear \Delta T from (12) :

\Delta T=\frac{Q}{m.c}   (13)

For Water:

\Delta T_{w}=\frac{Q_{w}}{m_{w}.c_{w}}   (14)

\Delta T_{w}=\frac{1kcal}{(1kg)(1 kcal/g\°C)}   (15)

\Delta T_{w}=1\°C)}   (16)

For Soil:

\Delta T_{s}=\frac{Q_{s}}{m_{s.c_{s}}   (17)

\Delta T_{s}=\frac{1kcal}{(1kg)(0.20 kcal/g\°C)}   (18)

\Delta T_{s}=5\°C)}   (19)

Hence the correct option is c.

5 0
3 years ago
Read 2 more answers
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