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Oksanka [162]
3 years ago
8

Let an n-protic acid be an acid that can donate n hydrogen ions and has the formula HnX. If 0.600 L of 0.400 M sodium hydroxide

is required to titrate 0.400 L of a 0.300 M HnX to the equivalence point, what is n in HnX?
Chemistry
1 answer:
vekshin13 years ago
5 0

Answer:

2, the acid is H₂X.

Explanation:

  • It is known at equivalence point: the no. of millimoles of base is equal to the no. of millimoles of acid.

<em>∴ (nMV) of NaOH = (nMV) for HnX.</em>

where, n is the no. of producible H⁺ or OH⁻ of the acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

  • For NaOH:

n = 1, M = 0.4 M, V = 0.6 L.

  • For HnX:

n = ???, M = 0.3 M, V = 0.4 L.

∴ n for HnX = (nMV) of NaOH / (MV) for HnX = (1)(0.4 M)(0.6 L)/(0.3 M)(0.4 L) = 2.

∴ the acid is H₂X.

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