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3 years ago

How many atoms of cobalt are in one formula unit of cobalt (III) oxide? one two three six

2 answers:

7 0

I believe the correct answer is the second option. There will be two cobalt atoms in one formula unit of cobalt (III) oxide. It has a chemical formula of Co2O3. This compound is does not naturally occur so it is being synthesized. It is mostly used as bleaching agent.

Vanyuwa [196]3 years ago

6 0

<u>Answer:</u> The correct answer is two cobalt atoms.

<u>Explanation:</u>

Cobalt (III) oxide is a compound which is formed by the combination of cobalt and oxygen atoms.

The oxidation state of cobalt in the compound is +3 and the oxidation state of oxygen in the compound is -2.

Thus, by criss-cross method, the oxidation states of the ions becomes the subscipt of the other atom which represents the number of individual atoms in a compound. So, the chemical formula of cobalt (III) oxide becomes $Co_2O_3$

In the given compound, 2 atoms of cobalt are present and 3 atoms of oxygen are there.

Thus, the correct answer is two cobalt atoms.

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______ reactions generate thermal energy in a nuclear power plant as water is changed into steam

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Fission reactions generate thermal energy

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3 years ago

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The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.

enot [183]

Answer:

$\large \boxed{\text{21.6 L}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 24.5

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}$

(b) Moles of CO₂

$\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}$

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37 °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

$\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}$

7 0

2 years ago

What is the volume of a balloon of gas at 842 mm Hg and -23° C, if its volume is 915 mL at a pressure of 1,170 mm Hg and a tempe

garik1379 [7]

Answer:
V₂ = 1070 mL or 1.07 L

Solution:

Data Given;
P₁ = 1170 mmHg

V₁ = 915 mL

T₁ = 24 °C + 273 K = 297 K

P₂ = 842 mmHg

V₂ = ?

T₂ = - 23 °C + 273 K = 250 K

According to Ideal gas equation,

P₁ V₁ / T₁ = P₂ V₂ / T₂

Solving for V₂,

V₂ = P₁ V₁ T₂ / P₂ T₁

Putting Values,

V₂ = (1170 mmHg × 915 mL × 250 K) ÷ (842 mmHg × 297 K)

V₂ = 1070 mL or 1.07 L

5 0

3 years ago

All organic molecules have what element in common

joja [24]

Every organic molecules/compound contains carbon (c).

Some other very abundant are hydrogen, nitrogen, oxygen, phosphorus, and sulfur.

I learned this with the acronym CHNOPS.

C - Carbon

H - Hydrogen

N - Nitrogen

O - Oxygen

P - Phosphorus

S - Sulfur

Hope this helps!

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3 years ago

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Sodium hydroxide, NaOH, reacts with sulfuric acid, H,SO,, in a neutralization reaction to

RSB [31]

Answer:

10.6 grams is approximately 0.10 moles. So you would need about 0.10 moles of sulfuric acid. That converts to about 9.80 grams.

Explanation:

hi girl i also wrote this in my test today so maube i hope it is correct.

mark me as brainliest if it helped you

7 0

2 years ago