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nalin [4]
4 years ago
14

Your ears are sensitive to differences in pitch, but they are not very sensitive to differences in intensity. You are not capabl

e of detecting a difference in sound intensity level of less than 1 dB. By what factor does the sound intensity increase if the sound intensity level increases from 60 dB to 61 dB
Physics
1 answer:
VLD [36.1K]4 years ago
3 0

Answer:

1.29

Explanation:

The level of intensity of sound (β) (in decibels, dB) is given by:

β  =  10log_{10}(\frac{I}{I_0} ), where I = sound intensity in watts per meter squared and I_0 = reference intensity.

Change in sound intensity level (Δβ) = \beta _2 - \beta _1 = 61 - 60 = 1

Δβ = 10log_{10}(\frac{I_2}{I_0}) - 10log_{10}(\frac{I_1}{I_0}) = 1

       10log_{10}(\frac{I_2}{I_0})/(\frac{I_1}{I_0}) = 1

       10log_{10}(\frac{I_2}{I_1})   = 1

               \frac{I_2}{I_1} = 10^{0.1} = 1.29

Hence, the sound intensity will increase by a factor of 1.29.

     

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The solid right-circular cylinder of mass 500 kg is set into torque-free motion with its symmetry axis initially aligned with th
aivan3 [116]

Answer:

30.95°

Explanation:

We need to define the moment of inertia of cylinder but in terms of mass, that equation say,

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Replacing the values we have,

A=\frac{1}{12}(500)(3(0.5)^2+(2)^2)A=197.9kg.m^2

At the same time we can calculate the mass moment of intertia of cylinder but in an axial way, that is,

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c=\frac{1}{2}(500)(0.5)^2

c=62.5kg.m^2

Finally we need to find the required angle between the fixed line a-a (I attached an image )

\Phi = 2tan^{-1}\sqrt{\frac{(\frac{A}{cos\gamma})^2-A^2}{c^2}}

Replacing the values that we have,

\Phi = 2tan^{-1}\sqrt{\frac{(\frac{197.9}{cos5\°})^2-197.9^2}{62.5^2}}

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\Phi = 2(15.47)

\Phi = 30.95\°

4 0
4 years ago
PHYSICS 50 POINTS PLEASE HELP
babymother [125]

Newton’s First Law of Motion - if an object is at rest, it takes un-

balanced forces to make it move. Conversely, if an object is moving

it takes an unbalanced force to make it change it’s direction or speed.

Newton was the first to see that such apparently diverse phenomena as a satellite moving near the Earth's surface and the planets orbiting the Sun operate by the same principle: Force equals mass multiplied by acceleration, or F=ma.

7 0
3 years ago
Read 2 more answers
What maximum force do you need to exert on a relaxed spring with a 1.2×104-n/m spring constant to stretch it 6.0 cm from its equ
Elena L [17]

Answer:

Maximum force will be equal to 720 N

Explanation:

We have given that spring constant k=1.2\times 10^4N/m

Maximum stretch of the spring x = 6 cm = 0.06 m

We have to find the maximum force on the spring

We know that spring force is given by

F=kx=1.2\times 10^4\times 0.06=720N

So the maximum force which is necessary to relaxed the spring will be eqaul to 720 N

6 0
4 years ago
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Pavel [41]

Answer:

m/s2 m/s

Explanation:

7 0
3 years ago
Suppose you do work on an object from rest to a certain speed v. Why does it take four times the amount of work to increase its
Otrada [13]
Answer: it is due to friction.

Explanation: if you were to push an object that is at rest, there is static friction that you would first need to overcome. An example would be pushing a car as it is in neutral. Pushing it takes more force and work to overcome that friction.
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Hope this helps!!!
8 0
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