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damaskus [11]
3 years ago
9

2. The water is then heated to its boiling point. Calculate the specific latent heat of

Physics
1 answer:
Law Incorporation [45]3 years ago
6 0

Answer:

2465 J/g

Explanation:

The amount of energy required to boil a sample of water already at boiling point is given by

Q=m\lambda_v

where

m is the mass of the water sample

\lambda_v is the specific latent heat of vaporization of water

In this problem, we know

Q=813,600 J

m = 330 g

Solving the equation for \lambda_v, we find

\lambda_v = \frac{Q}{m}=\frac{813600}{330}=2465 J/g

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