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vlabodo [156]
3 years ago
9

Which one of the following is NOT a simple machine?

Physics
1 answer:
ivann1987 [24]3 years ago
6 0
It is hammer because hammers are not examples of a simple machine
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Words related to earthquake
Fofino [41]

Answer:

shock, tremble, fault, slip, temblor, upheaval, trembler

undulation

macroseism

seimicity

seismism

Explanation:

3 0
3 years ago
Water drips from the nozzle of a shower onto the floor 193 cm below. The drops fall at regular (equal) intervals of time, the fi
Law Incorporation [45]

Answer: 108.81 cm and 48.66 cm

Explanation:

In this, we have to make sure to keep in mind the Gravity effects on the drops. The drops will accelerate when they fall making them travel faster. This means, the velocity is not constant.

What is know:

Height (h) = 193 cm

Gravity (g) =  981 cm/s^{2}

Initial Velocity = 0

First, we can know how long it take to the drop to travel to the floor. It can be done with the following equation:

x = V_{0} t + \frac{1}{2} at^{2}    (1)

Where:

x is the distance which is 193cm

Vo is the Initial Velocity  which is zero

t is the time the time it takes the drop to travel from the shower to the floor

a is the aceleration, which in this case is the gravity.

With the Initial Velocity equals zero the equations simply:

193 cm = \frac{1}{2}gt^{2}

To search for the time:

t =\sqrt{\frac{2*193cm}{981cm/s^{2} } }

t = 0.627 s

This is the time it takes a drop to fall to the floor, with this time and knowing other 3 drops have driped from the shower by this time. We can calculate how much time it takes the shower to drip each drop.

Time for Drip = t/4

Time for Drip = 0.156

This time is the difference between each drop, using the same equation we can calculate where was each drop, because now it is know how much time had each drop after being drip from the shower.

Our first is already on the floor (193 cm) with 0.627 s, The second drops have been falling for (0.627s - 0.156) 0.471 s and our third drop for (0.627s - 0.156 - 0.156) 0.315 s

We can use (1) to know how far have each drop traveled on these times. We know the Initials Velocity are 0, know we need ot know the distances.

For the second drop:

x = \frac{1}{2} (981cm/s^{2})(0.471s)^{2}

x =108.81 cm

For the third drop:

x = \frac{1}{2} (981cm/s^{2})(0.315s)^{2}

x = 48.66 cm

8 0
3 years ago
Health related components of fitness
alexgriva [62]

Answer:

Cardiovascular Endurance.

Muscular Strength.

Muscular endurance.

Flexibility.

Body Composition.

Explanation:

7 0
3 years ago
A thin flake of mica (n ! 1.58) is used to cover one slit of a double-slit interference arrangement. The central point on the vi
Darina [25.2K]

Answer: 6.64 × 10^ -6 m

Explanation:

for a constructive interference;

ρ= 2πm

remember that we are looking for the seventh bright side fringe.

so, m=7

ρ=14π

We now have to find the phase different

ρ`=2πx/ρ - 2πx/ρ

p` is the wavelenght in the mica. x= width of the mica wavelength in the mica.

ρ= ρ/n.

n= refractive index.

The phase will now be

ρ`= 2πx/ρ - 2πx = 2πx(n-1)/ρ.

ρ= ρ`

14π = 2πx (n-1)/ ρ

we now solve for x; x = 7ρ/n-1

x = 7(550× 20^ 9)/ 1.58 - 1

= 6.64 × 10^-6

4 0
3 years ago
Denis throws a ball downward at an initial speed of 15 m/s from the top of a cliff. (a)
Gennadij [26K]

Answer:

Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s.

Explanation:really sorry if it wrong,i mean reallyyyyy

4 0
3 years ago
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