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babunello [35]
2 years ago
13

How do conditions change as the depth of the ocean water increases?

Chemistry
2 answers:
Doss [256]2 years ago
7 0

Answer:

Explanation:

C

natta225 [31]2 years ago
5 0

Answer:

Temperature decreases and pressure increases

Explanation:

The water molecules pack together tighter as pressure increases –the pressure increase with depth, due to the weight of the water above, and causes the greatest density changes in seawater with depth (greater than the density changes due to temperature and salinity changes).

You might be interested in
Please help its difficult
Likurg_2 [28]

Answer:

pounds

pounds pounds pounds

8 0
3 years ago
An automobile gasoline tank holds 25.0 gal when full. how many pounds of gasoline will it hold if the gasoline has a density of
lora16 [44]

The amount (in pounds) the gasoline tank will hold when full is 153.76 lb

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

<h3>How to convert gallon to milliliters </h3>

1 gallon = 3785.412 mL

Therefore,

25 gallon = 25 × 3785.412

25 gallon = 94635.3 mL

<h3>How to determine the mass </h3>
  • Density = 0.737 g/mL
  • Volume = 94635.3 mL
  • Mass =?

Mass = Density × Volume

Mass = 0.737 × 94635.3

Mass = 69746.2161 g

<h3>How to convert grams to pounds </h3>

453.592 g = 1 lb

Therefore,

69746.2161 g = 69746.2161 / 453.592

69746.2161 g = 153.76 lb

Learn more about density:

brainly.com/question/952755

#SPJ1

4 0
2 years ago
How many grams are in o.3972 pounds?? Please explain..​
dsp73

Answer:

180.166889

Explanation:

for every 0.10 pounds is 45.3592 so just multiply that with how many pounds you have and there is your answer please give me the brainliest answer?

:) Hoped this helped!!! Have a good day!!! <3

6 0
4 years ago
Consider the mechanism. step 1:step 2:overall:2a⟶bb c⟶d2a c⟶dslowfast determine the rate law for the overall reaction, where the
Ne4ueva [31]

Answer:

Rate: R = k [A]²

Explanation:

The rate law equation for a given complex chemical reaction is given as the product of molar concentrations of the reactant raised to the power their respective partial reaction orders. The sum of the partial reaction orders is equal to the overall order of reaction.

For a complex reaction, the rate law is generally determined by the slowest step, which is known as the rate-determining step.

<u>Given reaction mechanism:</u>

Step 1: 2 A⟶ B,               slow step

Step 2: B+ C⟶ D,            fast step

Overall: 2 A + C ⟶ D

In this given reaction mechanism, the <em>step 1 is the slow step and thus the rate determining step.</em>

Therefore, the rate law for the given mechanism is:

Rate: R = k [A]²

Here, k is the overall rate constant

Also, the overall order of the reaction = 2

Therefore, the given chemical reaction is said to be second order reaction.

3 0
3 years ago
How are chemical reactions used in art​
Aliun [14]

Answer:

Chemistry reactions are used in art for the following processes;

1) Analog photography

The photographic paper used in analog photography react when exposed to light such that the image on the film stains the photopaper

A series of chemicals are further used to develop the images now carried on the paper and water is used to rinse of the chemicals after the other chemical processes are complete

The photopaper, now bearing the developed photo is hung for it to be dried

2) Paint used for painting consists of several chemicals, including, minerals that serve as pigment, oils that serve as carrying agent, a thinner to prevent the paint from turning to solid

An artist therefore combines different chemicals for a given paint task

3) In the sculpting process

An original sculpture is produced by the artist with the aid of clay or plaster, from the original sculpture, on which wax coatings and chemicals are used to make a replica mold.

Copies of the sculpture can then be made by pouring material into the mold

Explanation:

7 0
2 years ago
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