Answer:
Iodine have higher atomic size than tellurium because of the presence of more number of protons and lower atomic mass than tellurium because of the presence of lower number of neutrons.
Explanation:
Atomic number of an element is the number of the protons present in the element.
Atomic mass is the sum of a protons and the neutrons which are present in the nucleus of the atom.
Iodine has higher atomic number than tellurium because it has more number of protons than the tellurium.
On the other hand, iodine has lower atomic mass than tellurium because it has less number of neutrons in its core.
The answer to your question is,
Metalloids. They are a mix of elements that are both metals and non-metals in one.
-Mabel <3
Answer:
30.8 grams of magnesium hydroxide will form from this reaction, and magnesium nitrate is the limiting reagent.
Explanation:
The reaction that takes place is:
- 2NaOH + Mg(NO₃)₂ → 2NaNO₃ + Mg(OH)₂
Now we <u>convert the given masses of reactants to moles</u>, using their respective <em>molar masses</em>:
- 68.3 g NaOH ÷ 40 g/mol = 1.71 mol NaOH
- 78.3 g Mg(NO₃)₂ ÷ 148.3 g/mol = 0.528 mol Mg(NO₃)₂
0.528 moles of Mg(NO₃)₂ would react completely with (0.528 * 2) 1.056 moles of NaOH. There are more than enough NaOH moles, so NaOH is the reagent in excess and <em>Mg(NO₃)₂ is the limiting reagent.</em>
Now we <u>calculate how many Mg(OH)₂ are produced</u>, using the <em>moles of the limiting reagent</em>:
- 0.528 mol Mg(NO₃)₂ *
= 0.528 mol Mg(OH)₂
Finally we convert Mg(OH)₂ moles to grams:
- 0.528 mol Mg(OH)₂ * 58.32 g/mol = 30.8 g
Only one atom because atom with 17 electrons need that one electron to become stable