Answer:
it woul be 263
Explanation:
becaue it adds up like that
The answer is D jessim should spin the glove quickly while walking in a circle around nancy.
The formula for Keq for the first chemical reaction with
given Keq is:
<span>Keq 1 = [ HI ]^2 / [ H2 ] [ I2 ]</span>
<span>While the formula for Keq for the 2nd is:</span>
<span>Keq 2 = [ HI ] / [
H2 ]^(1/2) [ I2 ]^(1/2)</span>
We can see that the coefficients in the reaction are
equal to the exponents in the equilibrium equation. Therefore if we divide the
whole reaction by 2, then that means we have to take the square root of the
equilibrium equation. Or in this case,
Keq 2 = sqrt (Keq 1)
Keq 2 = sqrt (794)
<span>Keq 2
= 28.19</span>
- Standard reduction potential of Ag/Ag⁺ is 0.80 v and that of Cu⁺²(aq)/Cu⁰ is +0.34 V.
- The couple with a greater value of standard reduction potential will oxidize the reduced form of the other couple.
Ag⁺ will be reduced to Ag(s) and Cu⁰ will be oxidized to Cu²⁺
Anode reaction: Cu⁰(s) → Cu²⁺ + 2 e⁻ E⁰ = +0.34 V
Cathode reaction: Ag⁺(aq) + e → Ag(s) E⁰ = +0.80 V
Cell reaction: Cu⁰(s) + 2 Ag⁺(aq) → Cu⁺²(aq) + 2 Ag⁰(s)
E⁰ cell = E⁰ cathode + E⁰ anode
= 0.80 + (-0.34) = + 0.46 V