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Dmitry [639]
3 years ago
10

How to find protons, neutrons, electrons of an element.

Chemistry
1 answer:
Zina [86]3 years ago
5 0
Find your element on the periodic table. Locate the element’s atomic number.
 Determine the number of electrons.  Look for the atomic mass of the element. Subtract (-) the atomic number from the atomic mass
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A solution is prepared at that is initially in benzoic acid , a weak acid with , and in sodium benzoate . Calculate the pH of th
Kisachek [45]

Answer:

pH=4.1

Explanation:

Hello,

In this case, for a concentration of 0.42 M of benzoic acid whose Ka is 6.3x10⁻⁵ in 0.33 M sodium benzoate, we use the Henderson-Hasselbach equation to compute the required pH:

pH=pKa+log(\frac{[base]}{[acid]} )

Whereas the concentration of the base is 0.33 M and the concentration of the acid is 0.42 M, thereby, we obtain:

pH=-log(Ka)+log(\frac{[base]}{[acid]} )\\\\pH=-log(6.3x10^{-5})+log(\frac{0.33M}{0.42M} )\\\\pH=4.1

Regards.

3 0
3 years ago
An alpha particle is equivalent to the nucleus of an atom of which element?(1 point)
Monica [59]

Answer: An alpha-particle is identical to the nucleus of a normal (atomic mass four) helium atom i.e. a doubly ionised helium atom. Alpha particles (also termed alpha radiation or alpha rays) was the first nuclear radiation to be discovered, beta particles and gamma rays were identified soon after.

7 0
2 years ago
What is the ph of a 0.027 M KOH solution?
Monica [59]
First you calculate the concentration of [OH⁻] in <span>solution :

POH  = - log [ OH</span>⁻]

POH = - log [ 0.027 ]

POH = 1.56

PH + POH = 14

PH + 1.56 = 14

PH = 14 - 1.56

PH = 12.44

hope this helps!

8 0
3 years ago
The pK of acetic acid is pK = 4.76. For a 0.1 M solution of acetic acid at a pH = 4.76 what is the concentration of [H+]?
spin [16.1K]

Answer:

[H+] = 1.74 x 10⁻⁵

Explanation:

By definition pH = -log  [H+]

Therefore, given the pH,  all we have to do is  solve algebraically for  [H+] :

[H+]  = antilog ( -pH ) =  10^-4.76 = 1.74 x 10⁻⁵

6 0
3 years ago
Convert 3841 cL to L. SHOW WORK PLS
barxatty [35]

Answer:

1 cl = 1 * 10-5 m³

1 L = 1 * 10-3 m³

1 L = 0.001 m³

1 m³ = (1/0.001) L

1 m³ = 1000 L

1 cl = 1 * 10-5 * 1000 L

1 cl = 0.01 L

4 0
2 years ago
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