A 15 g turntable is covered with a uniform layer of dry ice that has a mass of 9.0 g. The angular speed of the turntable and dry
ice is initially 0.75 rad/s. What is the angular speed of the turntable once all the dry ice has evaporated?
1 answer:
Answer:
1.2 rad/s
Explanation:
m1 = 15 g, m2 = 9 g, ω1 = 0.75 rad/s
Let the new angular speed is ω2 and the radius of the table be r.
The angular momentum is conserved when no external torque is applied.
I1 ω1 = I2 ω2
(m1 + m2)x r^2 x 0.75 = m1 x r^2 x ω2
(15 + 9) x 0.75 = 15 x ω2
ω2 = 1.2 rad/s
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