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Mekhanik [1.2K]
3 years ago
7

Which three statements about electromagnetic radiation are true?

Physics
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer:

Option (1), (3) and (4) are correct.

Explanation:

When the oscillating electri and magnetic field interacts perpendicularly to each other, the electromagnetic radiations are produced. The electromagnetic radiations propagates in the perpendicular direction of both electric and magnetic field vectors.

For example, gamma rays, X rays, ultra violet rays, visible radiations, infrared rays, micro waves and radio waves.

Electromagnetic radiations do not require any medium for their propagation.

They do not carry mass, they carry energy only.

zvonat [6]3 years ago
3 0

-- Light is electromagnetic radiation.

-- Electromagnetic radiation has no mass.

-- Electromagnetic radiation can travel through vacuum.

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. A 79 g sample of water at 21oC is heated until it becomes steam with a temperature of 143oC. Find the change in heat content o
mote1985 [20]

Answer:

40479.6 J

Explanation:

Applying,

q = cm(t₂-t₁).................... Equation 1

Where q = change in heat content of the system, c = specific heat capacity of the system, m = mass of the system, t₁ = initial temperature, t₂ = final temperature.

From the question,

Given: m = 79 g = 0.079 kg, t₁ = 21°C, t₂ = 143°C

Constant: c = 4200 J/kg.°C

Substitute these values into equation 1

q = 4200(0.079)(143-21)

q = 331.8(122)

q = 40479.6 J

4 0
3 years ago
At the top of a hill a roller coaster has gravitational potential energy due to its position. What happend to this potential ene
Anuta_ua [19.1K]

As the roller coaster speeds up on the way down the hill, the potential energy of  roller coaster will be converted to kinetic energy.

<h3>What is Conservation of Energy ?</h3>

Conservation of energy state that energy is neither created nor destroy, they can only be transformed from one form to another. Energy of and object can transform from Potential energy to kinetic energy and vice versa

Given that at the top of a hill a roller coaster has gravitational potential energy due to its position. What will happen to this potential energy as the roller coaster speeds up on the way down the hill is that the potential energy to the roller coaster will start decreasing while the kinetic energy will start to increase.

The total energy of the roller coaster will be constant because of conservation of energy. As the roller coaster speeds up on the way down the hill, the potential energy will eventually reduce to zero where the total energy of the as the roller coaster will be equal to maximum kinetic energy.

Therefore, as the roller coaster speeds up on the way down the hill, the potential energy of  roller coaster will be converted to kinetic energy.

Learn more about Energy here: brainly.com/question/25959744

#SPJ1

3 0
2 years ago
.Golden Rice is an example of genetically modified organism. <br> true or false
MissTica

Answer:

True

Explanation:

Golden Rice is an example of genetically modified organism.

7 0
3 years ago
Read 2 more answers
A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. its speed is 40 m/s when i
Alenkinab [10]

Given that,

Initial velocity , Vi = 0

Final velocity , Vf = 40 m/s

Acceleration due to gravity , a = 9.81 m/s²

Distance can be calculated as,

2as = Vf² - Vi²

2 * 9.81 *s = 40² - 0²

s = 81.55 m

For half height, that is, s = 40.77m

Vf= ??

2as = Vf² - Vi²

2 * 9.81 * 40.77 = Vf² - 0²

Vf² = 800

Vf = 28.28 m/s

Therefore, speed of roller coaster when height is half of its starting point will be 28 m/s.  

5 0
3 years ago
Two identical charges,2.0m apart,exert forces of magnitude 4.0 N on each other.What is the value of either charge?
storchak [24]

Answer:

\large \boxed{42\, \mu \text{C}}$

Explanation:

The formula for the force exerted between two charges is

F=k \dfrac{ q_1q_2}{r^2}

where k is the Coulomb constant.

The charges are identical, so we can write the formula as

F=k\dfrac{q^{2}}{r^2}

\begin{array}{rcl}\text{4.0 N}& = & 8.988 \times 10^{9}\text{ N$\cdot$m$^{2}$C$^{-2}$} \times \dfrac{q^{2}}{\text{(2.0 m)}^{2}}\\\\4.0 & = & 2.25 \times 10^{9}\text{ C$^{-2}$} \times q^{2}\\\\q^{2} & = & \dfrac{4.0}{2.25 \times 10^{9}\text{ C$^{-2}$}}\\\\& = & 1.78 \times 10^{-9} \text{ C}^{2}\\q & = & 4.2 \times 10^{-5} \text{ C}\\& = & 42\, \mu \text{C}\\\end{array}\\\text{Each charge has a value of $\large \boxed{\mathbf{42\, \mu }\textbf{C}}$}

7 0
3 years ago
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