Answer:
28.6 ohm
Explanation:
there is a 3rd resistor in series. voltage drop across the resistors will be equal to 60v
7*.2+7*.2 +.2x = 60
2.8+.2x = 60
.2x = 57.2
x = 28.6
If the resistance of each bulb is 3 ohms, and they are connected across the battery, then current will flow through them.
In series, the two 3-ohm bulbs will look like a single 6-ohm resistance.
Current = (voltage) / (resistance) = (12v) / (6 ohms) = 2 Amperes.
The battery will need to deliver some power to the circuit.
Power = (voltage) x (current) = (12v) x (2 Amperes) = 24 watts .
Each bulb will dissipate 12 watts, in the form of light and heat.
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They are called <span>Frequency-modulated</span>
Answer:
The intensity of light passing from the third polarizer is 3Io/16.
Explanation:
The law of Malus is given by

Let the incident intensity of light is Io.
The intensity of light passing from the first polarizer is

The intensity of light passing from the second polarizer is

The intensity of light passing from the third polarizer is

Answer:
Following are the solution to the given question:
Explanation:
Please find the complete question in the attached file.


Distance:

