You have a 1.8 M solution of HCI. You need to make a 0.70 M solution with a volume of 550 mL. How many mL of the stock solution
1 answer:
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Answer:
1.b. 2.5 mol
2.c.82.8%
3.d. synthesis
4.c . 2:2
5.d. 5 moles
6.c.5.02
7.d.3:1
8.d.2.68 moles
Explanation:
1.
Here , 2 mole of RbNO3 will produce, 1 mole of O2
1 mole of RbNO3 will produce =
mole of O2
5 mole of RbNO3 will produce =
<u>= 2.5 mole of O2</u>
2 .
Molar mass of HCl = 1 + 35.45 = 36.45 gram
Molar mass of CO2 = 12 +32 = 44 gram
1 mole of the substance = molar mass
So , 1 mole of HCl = 36.45 gram
2 mole of HCl = 2 x 36.45 =72.9 gram
1 mole of CO2 = 44 gram
The given equation is :
Here CaCO3 is the excess reagent and HCl is the limiting reagent
2 mole of HCl will produce = 1 mole of CO2
72.9 gram of HCl= 44 gram of CO2
so, 1 gram of HCl =
gram of CO2
Here we need to calculate the mass of CO2 in 200 gram of HCl.
So, 200 gram of HCl =
gram CO2
=120.71 gram CO2
this is the theoritical yield of CO2 = 120.71 gram
Experimental yield = 100 gram (given)
The percent yield is calculated by:
= 82.84%
3.Synthesis Reaction : Those reactions in which two or more substances combine to give a single product.
Here NH3 and HCl are combined and giving only one product = NH4Cl
4.
Hydrogen = H2
Water = H2O
Here Ratio of H2 to H2O is 2:2
5.The balanced equation is :
The number of atoms on left side should be equal to the right side:
Ca = 1
H = 4
O = 2
Cl = 2
Here, 2 moles of water(H2O) = 2 moles of HCl
So, 5 moles of water will give = 5 moles of HCl
6.
Molar mass of AgNO3 = 169.87 g/mol
1 mol of AgNO3 = 169.87 gram
Molar mass of AgCl = 143.32 g/mol
1 mole of AgCl = 143.32 grams
According to the given equation ,
2 mole of AgNO3 will give = 2 mole of AgCl
1 mole of AgNO3 = 1 mole of AgCl
169.87 gram of AgNO3 = 143.32 gram of AgCL
1 gram of AgNO3 =
5.95 gram of AgNO3 =
= 5.02 grams
7. The mole ratio of Hydrogen (H2) to Nitrogen (N2):
H2 = 3 mole
N2 = 1 mole
[H2]:[N2] = 3:1
8. The moles in a substance can be calculated by using :
Mass of N2 = 75 grams (Given)
Molar mass = 28 gram
Moles = 2.678 moles
