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Tanzania [10]
3 years ago
5

Why are infrared waves located between microwaves and visible light on the electromagnetic spectrum?

Physics
1 answer:
dangina [55]3 years ago
3 0

Answer: The infra red waves is located between microwave and visible light based on their WAVELENGTH and FREQUENCY of occurrence.

Explanation:

Electromagnetic waves are those waves that do not require or need a material medium for its propagation, but they are able to travel through a vacuum. They exhibit or show all properties associated or connected with light. They are undeflected in electric and magnetic fields. These electromagnetic waves are arranged in order of their FREQUENCY and WAVELENGTHS which is known as ELECTROMAGNETIC SPECTRUM.

FREQUENCY is defined as the number of cycles which the wave completes in one second and is measured in Hertz(Hz). While WAVELENGTH is defined as the distance between two successive crests or troughs of waves which is measured in meter (m).

The electromagnetic spectrum is made up of the following rays which is arranged from the biggest wavelengths to the smallest:

--> Radiowaves

--> microwave :

--> infrared rays:

--> visible light:

--> ultraviolet rays

--> x-rays and

--> Gamma rays.

According to the arrangement of the spectrum above, the microwave has a higher wavelength and frequency than the infrared rays, while the visible light has a lower wavelength and frequency than the infrared rays.

You might be interested in
Help me understand why 5G cell phones and cell phone towers do not cause cancer even with prolonged exposure and are not harmful
Nat2105 [25]

Answer:

I'm not really sure as far as cell phone towers, but 5G hasn't published any safety tests, so we don't know for sure whether or not this would be harmful/cancer causing. The lack of evidence in either direction may be why we can't say definitively that it is safe or not harmful. Hope this helps.

Explanation:

7 0
3 years ago
A truck is speeding up as it travels on an interstate. The truck's momentum (in kg · m/s) is proportional to the truck's speed (
serious [3.7K]

Answer:

a)48300 times

b)P = 821100  kg · m/s

Explanation:

Given that

m = 48300 kg

v= 23 m/s

We know that linear momentum (P) given as

P = m v

P = 48300 x 23  kg · m/s

So we can say that truck momentum is 48300 times its velocity.

Now given that

v= 17 m/s

P = m v

P = 48300 x 17  kg · m/s

P = 821100  kg · m/s

6 0
4 years ago
Read 2 more answers
If continuous spectrum light from a star passes through a cool, low-density gas on its way to your telescope and spectroscope, _
natima [27]

Answer: a dark (absorption) line

Explanation:

This is as a result of absorption of electromagnetic a specific wavelength. The pattern followed by such lines is characteristic of specific atoms in the path of radiation.

6 0
3 years ago
A projectile is fired with an initial speed of 100 m/s and angle of elevation 30 degrees. The projectile eventually hits the gro
zaharov [31]

Answer:

Explanation:

Given

launch velocity u=100\ m/s

Launch angle \theta =30^{\circ}

Range of Projectile R=\frac{u^2\sin 2\theta }{g}

R=\frac{100^2\times \sin (2\times30)}{9.8}

R=883.699\approx 883.7

Horizontal velocity remain same and only vertical velocity changes.

Initially  vertical  velocity is in upward direction but as soon as it reaches the ground its direction change but magnitude remain same.

u_y=100\sin (30)=50\ m/s

u_x=100\cos (30)=86.60\ m/s

u_{net}=\sqrt{(50)^2+(86.60)^2}

u_{net}=99.99\approx 100\ m/s      

7 0
3 years ago
How would i solve these problems, nobody in my class understands and there is a substitute
DiKsa [7]

1) X-component: 568.5 N, Y-component: 511.9 N

2) The horizontal force is 86.6 N and the resulting acceleration is 0.87 m/s^2

Explanation:

1)

In this first part of the problem, we have to resolve the force into its two components, along the x and the y direction.

The two components are given by:

F_x = F cos \theta\\F_y = F sin \theta

where

F = 765 N is the magnitude of the force

\theta=42.0^{\circ} is the angle of the force with the horizontal

Substituting, we find:

  • Horizontal component: F_x = (765)(cos 42.0^{\circ})=568.5 N
  • Vertical component: F_y = (765)(sin 42.0^{\circ})=511.9 N

2)

First of all, we have to find the horizontal component of the pulling force, which is given by

F_x = F cos \theta

where

F = 100 N is the magnitude of the pulling force

\theta=30.0^{\circ} is the direction of the force with the horizontal

Substituting,

F_x = (100)(cos 30^{\circ})=86.6 N

Now we can find the acceleration of the wagon by using Newton's second law:

F_x = ma_x

where

F_x = 86.6 N is the net force in the horizontal direction

m = 100 kg is the mass of the wagon

a_x is the acceleration in the horizontal direction

Solving for a_x, we find

a_x = \frac{F_x}{m}=\frac{86.6}{100}=0.87 m/s^2

Learn more about vector components:

brainly.com/question/2678571

And about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0
3 years ago
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