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Tresset [83]
4 years ago
7

A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is 15.93nm. What is the total wid

th of a crystal in millimeters 105 molecules across? Write your answer as a decimal.
Chemistry
1 answer:
salantis [7]4 years ago
8 0

0.00167265 mm

Explanation:

Given the spacing between the molecules in the crystal is 15.93 nm.

1 nm = 10^{-9} m

so 15.93 nm = 15.93 * 10^{-9} = 1.593 * 10^{-8} m

Spacing between 2 molecules is  1.593 * 10^{-8} m

So total width of 105 molecules crystal is 1.593 * 10^{-8} *105 = 167.265 * 10^{-8} m

We know that

1 m = 1000 = 10^{3} mm

So total width of 105 molecules crystal in millimeters is 167.265 * 10^{-8}  *10^{3}

 = 167.265 * 10^{-5} = 1.67265 * 10^{-3} mm = 0.00167265 mm

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Which properties do all solids share?
Lera25 [3.4K]

Answer:

c

Explanation:

because when you hold a solid in your hand does it move does it shift no it stays the same so it doesn't take the form of the container it's in cuz that's a liquid.

4 0
3 years ago
Why are the coefficients before a chemical symbol important?​F. ​ They show the number of elements in each molecule.​G. ​ They i
Valentin [98]

Answer:They indicate the number of molecules of each substance

Explanation:

When we write chemical reaction equations, we usually put a number before the symbol of each reactant.

These coefficient shows the number of molecules of that specie that is involved in the balanced reaction equation for the reaction.

These coefficients are important because they are used in carrying out stoichiometric calculations.

7 0
3 years ago
Nitrogen gas at 300 k and 200 kpa is throttled adiabatically to a pressure of 100 kpa if the change in kinetic energy is negligb
erastovalidia [21]

Answer:

The temperature of the Nitrogen after throttling is  T_2 = 300 \  K

Explanation:

From the question we are told that

   The  temperature is  T_1 =  300 \  K

    The pressure is  P =  200 \  kPa  =  200 * 10^{3} \  Pa

    The pressure after being  P_1 =  100 \  kPa =  100 * 10^{3} \  Pa

   

Generally from the first law of thermodynamics we have that

      Q - W =  \Delta U + \Delta  K

Here \Delta U  is the change internal  energy which is mathematically represented as

            \Delta U =  C_p  (T_2 - T_1)

Here      C_p is the specific heat of the gas at constant pressure

        \Delta K  is the change kinetic energy which is negligible

         Q  is the thermal  energy  which is Zero for an adiabatic process

         W  is the work done and the value is zero given that the gas was throttled adiabatically

So

      0=  \Delta U +0

=>   \Delta U  = 0

=>  (T_2 - 300)  = 0

=>   T_2 = 300 \  K

     

3 0
3 years ago
What will be the pH of a buffer solution containing an acid of pKa7.5, with an acid concentration exactly one fourth of that of
I am Lyosha [343]

Answer: pH of buffer solution is 8.1

Explanation:

The formula for the Henderson–Hasselbalch equation is:

pH=pK_a+\log\frac{[A^-]}{[HA]}

pH is the concentration of [H^+]

pK_a is the acid dissociation constant,

A^- and HA are concentrations of the conjugate base and starting acid.

Putting in the values we get:

pH=7.5+\log\frac{x}{\frac{x}{4}}

pH=8.1

Thus pH of buffer solution is 8.1

3 0
3 years ago
Isopropyl alcohol is mixed with water to produce a 32.0 % (v/v) alcohol solution. How many milliliters of each component are pre
Sonja [21]

<u>Answer:</u> The volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL

<u>Explanation:</u>

We are given:

32.0 % (v/v) alcohol solution

This means that 32 mL of isopropyl alcohol is present in 100 mL of solution

Volume of water = 100 - 32 = 68 mL

Volume of solution given = 795 mL

Applying unitary method:

In 100 mL of solution, the volume of isopropyl alcohol present is 32 mL

So, in 795 mL of solution, the volume of isopropyl alcohol present will be = \frac{32}{100}\times 795=254.4mL

Volume of water in given amount of solution = 795 - 254.4 = 540.6 mL

Hence, the volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL

4 0
4 years ago
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