No of atoms in 4.8 dm³ of neon gas is determined in the following way.
Explanation:
We have given
Neon Gas=4.8dm³
At STP
1 mole of an ideal gas occupies 22.4 L(dm³) of volume.
which means that number of molecules occupy 22.4 L of volume.
So
4.8 dm³x 1 mole/22.4 dm³ = 0.214 moles Neon
0.214 moles x 6.02x10²³ atoms/mole = 1.29x10²³ atoms of Neon
No of Atoms in 4.8dm3 neon gas =1.29x10²³ atoms of Neon
To know more about this :
https://brainly.in/question/2122177
https://brainly.in/question/2419625
Enthalpy is the change in energy. A cold pack will react endothermically and enthalpy will be positive and a heat pack will have negative enthalpy. You cannot determine which has more change in enthalpy unless you measure the temperature change. Eg. a heat pack went from 25c to 35c will have greater change in enthalpy then a cold pack going from 25 to 20c because the net temperature difference is greater
Answer:
Cystic fibrosis (CF) is a genetic disease that causes thick, sticky mucus to build up in organs, including the lungs and the pancreas. In a healthy person, mucus that lines organs and body cavities, such as the lungs and the nose, is slippery and watery. In people with CF, thick mucus clogs causes symptoms in the lungs and pancreas.
Explanation:
The causes of CF
Who is affected
Symptoms and treatments
How CF is diagnosed in children and adults
Tips on living with CF
I believe the answer is a definition.
Answer:
Reaction 1: Kc increases
Reaction 2: Kc decreases
Reaction 3: The is no change
Explanation:
Let us consider the following reactions:
Reaction 1: A ⇌ 2B ΔH° = 20.0 kJ/mol
Reaction 2: A + B ⇌ C ΔH° = −5.4 kJ/mol
Reaction 3: 2A⇌ B ΔH° = 0.0 kJ/mol
To predict what will happen when the temperature is raised we need to take into account Le Chatelier Principle: when a system at equilibrium suffers a perturbation, it will shift its equilibrium to counteract such perturbation. This means that <em>if the temperature is raised (perturbation), the system will react to lower the temperature.</em>
Reaction 1 is endothermic (ΔH° > 0). If the temperature is raised the system will favor the forward reaction to absorb heat and lower the temperature, thus increasing the value of Kc.
Reaction 2 is exothermic (ΔH° < 0). If the temperature is raised the system will favor the reverse reaction to absorb heat and lower the temperature, thus decreasing the value of Kc.
Reaction 3 is not endothermic nor exothermic (ΔH° = 0) so an increase in the temperature will have no effect on the equilibrium.
