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3 years ago

Please answer the question and explain

Chemistry

1 answer:

Sindrei [870]3 years ago

4 0

Answer:

x=30

Explanation:

I will try to explain with a drawing.

This is a rule of three.

If you are wondering what the rule of three is. It's when u have 3 informations and you solve.

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1. In class, students learned that a cart will move when a force of 50 N

zzz [600]

He did not apply the fifty newtons of greater force! Ok it says when it needed to have the greater force of fifty the person only put 10N out of the fifty, and left out 40N, that is why it did not work properly.

4 0

3 years ago

At 25∘C, the decomposition of dinitrogen pentoxide, N2O5(g), into NO2(g) and O2(g) follows first-order kinetics with k=3.4×10−5

Annette [7]

Answer:

4600s

Explanation:

$2N_{2}O_{5}(g) - - -> 4NO_{2}(g) +O_{2}$

For a first order reaction the rate of reaction just depends on the concentration of one specie [B] and it’s expressed as:

$-\frac{d[B]}{dt}=k[B] - - - -\frac{d[B]}{[B]}=k*dt$

If we have an ideal gas in an isothermal (T=constant) and isocoric (v=constant) process.

PV=nRT we can say that P = n so we can express the reaction order as a function of the Partial pressure of one component.

$-\frac{d[P(B)]}{P(B)}=k*dt$

$-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=k*dt$

Integrating we get:

$\int\limits^p \,-\frac{d[P(N_{2}O_{5})]}{P(N_{2}O_{5})}=\int\limits^ t k*dt$

$-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])=k(t_{2}-t_{1})$

Clearing for t2:

$\frac{-(ln[P(N_{2}O_{5})]-ln[P(N_{2}O_{5})_{o})])}{k}+t_{1}=t_{2}$

$ln[P(N_{2}O_{5})]=ln(650)=6.4769$

$ln[P(N_{2}O_{5})_{o}]=ln(760)=6.6333$

$t_{2}=\frac{-(6.4769-6.6333)}{3.4*10^{-5}}+0= 4598.414s$

4 0

3 years ago

Calculate the mass of nitric acid required to make a 250mL solution with 2.40 ph

meriva

The mass of nitric acid required to make the given solution is 0.0627 g.

The given parameters:

<em>Volume of the acid, V = 250 mL</em>
<em>pH of the acid, = 2.4</em>

The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;

$H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 0.00398$

The molarity of the nitric acid is calculated as follows;

$= 0.00398 \ H^+ \times \frac{1 \ M \ HNO_3}{1 \ H^+} \\\\= 0.00398 \ M$

The number of moles of the nitric acid is calculated as follows;

$moles = M\times L\\\\moles = 0.00398\ M \ \times \ \frac{250 \ mL}{1000} \\\\moles = 9.95 \times 10^{-4} \ mol.$

The molar mass of nitric acid is calculated as;

$HNO_3 = (1) \ + (14) \ + (16 \times 3) = 63 \ g/mol$

The mass of the nitric acid contained in the calculated number of moles is calculated as;

$mass = moles\ \times \ molar \ mass\\\\mass = 9.95\times 10^{-4} \ mol. \ \times \ 63 \ g/mol\\\\mass = 0.0627 \ g$

Thus, the mass of nitric acid required to make the given solution is 0.0627 g.

Learn more about molarity of acids here: brainly.com/question/13864682

3 0

2 years ago

How many liters of ammonia (NH3), at 3.2 atm and 23C, must be used to produce of 2.65 grams of calcium hydride (CaH2). 6 Ca(s)

7nadin3 [17]

Answer:

The answer to your question is V = 0.32 L

Explanation:

Data

Volume of NH₃ = ?

P = 3.2 atm

T = 23°C

mass of CaH₂ = 2.65 g

Balanced chemical reaction

6Ca + 2NH₃ ⇒ 3CaH₂ + Ca₃N₂

Process

1.- Convert the mass of CaH₂ to moles

-Calculate the molar mass of CaH₂

CaH₂ = 40 + 2 = 42 g

42 g ------------------ 1 mol

2.65 g -------------- x

x = (2.65 x 1)/42

x = 0.063 moles

2.- Calculate the moles of NH₃

2 moles of NH₃ --------------- 3 moles of CaH₂

x --------------- 0.063 moles

x = (0.063 x 2) / 3

x = 0.042 moles of NH₃

3.- Convert the °C to °K

Temperature = 23°C + 273

= 296°K

4.- Calculate the volume of NH₃

-Use the ideal gas law

PV = nRT

-Solve for V

V = nRT / P

-Substitution

V = (0.042)(0.082)(296) / 3.2

-Simplification

V = 1.019 / 3.2

-Result

V = 0.32 L

7 0

3 years ago

Write the molecular formula of potassium chloride

Naddik [55]

Answer:

KCl is the answers for the question

Explanation:

please give me brainlest

4 0

3 years ago

Read 2 more answers