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babymother [125]
3 years ago
15

Can someone help me?

Chemistry
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

<u>an element with a large number of valence electrons and a large atomic radius</u>

Explanation:

Electronegativity means a tedency when an atom attracts bonding electrons in a covalent bond situation.

» If an atom has many valency electrons [ <em>empty</em><em> </em><em>orbitals</em><em> </em><em>i</em><em>n</em><em> </em><em>o</em><em>u</em><em>t</em><em>e</em><em>r</em><em>m</em><em>o</em><em>s</em><em>t</em><em> </em><em>s</em><em>h</em><em>e</em><em>l</em><em>l</em><em> </em>], it has difficulty in attracting electrons hence electronegativity low.

» If an atom is large, its nuclear attraction force of incoming electrons is low hence low electronegativity.

.

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Use electron configurations to account for the stability of the lanthanide ions Ce⁴⁺ and Eu²⁺.
Citrus2011 [14]

Answer:

Explanation:

 The Ce metal has electronic configuration as follows

[Xe] 4f¹5d¹6s²

After losing 4 electrons , it gains noble gas configuration ,. So Ce ⁺⁴ is stable.

Eu  has electronic configuration as follows

[ Xe ] 4 f ⁷6s²

[ Xe ] 4 f ⁷

Its outermost orbit contains 2 electrons so  Eu²⁺ is stable. Its +3 oxidation state is also stable.

Ce⁺²

7 0
4 years ago
How many moles of Ag can be produced if 350. g of Cu are reacted with excess AgNO3 according to the equation Cu(s) + 2AgNO3(aq)
Ksju [112]
Hello.

balance the equation first 
<span>Cu + 2AgNO3 ----> [2Ag] + Cu(NO3)2 
</span>

<span>Now set up the equation </span>
<span>350gCu*(1molCu/ 63.546g Cu) * (2molAg/1molCu) * (107.8682g Ag/1molAg)
 </span>

<span>Cancel out 1molCu with 1molCu, and cancel out 2molAg with 1molAg (it still remains 2mol Ag) </span>

<span>You are left with </span>
<span>350gCu*(1/63.546g Cu)*(2Ag/1)* (107.8682g Ag/1) 
</span>

<span>350gCu*1*2*107.8682= 75507.74g 
</span>

<span>now divide 75507.74g by 63.546g 
</span>
<span>you get [1188.2374972460896g Ag]
</span>
Have a nice day
3 0
3 years ago
Read 2 more answers
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masha68 [24]

Answer:

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Explanation:

5 0
3 years ago
How many cm is 0.375 ft.​
ivann1987 [24]

Answer:

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Explanation:

8 0
3 years ago
Read 2 more answers
370 cm3 of water at 80°C is mixed with 120 cm3 of water at 4°C. Calculate the final equilibrium temperature, assuming no heat is
NikAS [45]

Answer : The final temperature of the mixture is 61.4^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

And as we know that,

Mass = Density × Volume

Thus, the formula becomes,

(\rho_1\times V_1)\times c_1\times (T_f-T_1)=-(\rho_2\times V_2)\times c_2\times (T_f-T_2)

where,

c_1 = c_2 = specific heat of water = same

m_1 = m_2 = mass of water  =  same

\rho_1 = \rho_2 = density of water = 1.0 g/mL

V_1 = volume of water at 80.0^oC  = 370cm^3=370mL

V_2 = volume of water at 4^oC  = 120cm^3=120mL

T_f = final temperature of mixture = ?

T_1 = initial temperature of water = 80.0^oC

T_2 = initial temperature of water = 4^oC

Now put all the given values in the above formula, we get:

(\rho_1\times V_1)\times (T_f-T_1)=-(\rho_2\times V_2)\times (T_f-T_2)

(1.0g/mL\times 370mL)\times (T_f-80.0)^oC=-(1.0g/mL\times 120mL)\times (T_f-4)^oC

T_f=61.4^oC

Therefore, the final temperature of the mixture is 61.4^oC

6 0
4 years ago
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