Question

The perimeter of a rectangle is 66 feet. Find its dimensions assuming that its length is 9 feet less than twice its width.

Answer 1

Answer:

Length = 19 feet

Width = 14 feet

Explanation:

The perimeter, P, of a rectangle is given by

$P=2(l+w)$

where l is the length and w is the width.

From the question, the length is 9 feet less than twice the width.

$l=2w-9$

Substitute this in the equation for the perimeter.

$P=2(2w-9+w)$

$P=2(3w-9)$

$66=2(3w-9)$

$33=3(w-3)$

$11=w-3$

$w=14$

Substitute for this in the equation for l.

$l=2w-9=2\times14-9=28-9=19$

Hence, the length is 19 feet and the width is 14 feet.