Acceleration = Change in Velocity / time
a = (v - u) / t
Where v = final velocity in m/s
u = initial velocity in m/s
t = time in seconds.
a = acceleration in m/s²
A proper record of the changes in velocity with the corresponding time would help find the acceleration.
Answer:
Explanation:
a ) work done by gravitational force
= mg sinθ ( d + .21)
Potential energy stored in compressed spring
= 1/2 k x²
= .5 x 431 x ( .21 )²
= 9.5
According to conservation of energy
mg sinθ ( d + .21) = 9.5
3.2 x 9.8 x sin 30( d + .21 ) = 9.5
d = 40 cm
b )
As long as mg sin30 is greater than kx ( restoring force ) , there will be acceleration in the block.
mg sin30 = kx
3.2 x 9.8 x .5 = 431 x
x = 3.63 cm
When there is compression of 3.63 cm in the spring , block will have maximum velocity. there after its speed will start decreasing.
Answer:
c
Explanation:
the question answered itself.
<span>93.3°C
A temperature in Fahrenheit (°F) can be converted to Celsius (°C), using the formula
[°C] = ([°F] − 32) × 5⁄9. Here we have to convert a temperature of 200°F in to Celsius. Thus Subtract 32 from Fahrenheit and multiply by 5 then divide by 9 .
That is (200°F - 32) × 5/9=168 × 5/9
=840/9
=93.333333333°C
= 93.3°C</span>
By ideal gas theory, cylinder b has the higher temperature.
We need to know about the ideal gas theory to solve this problem. The ideal gas can be represented by
P . V = n . R . T
where P is the pressure, V is volume, n is the number of molecules, R is the ideal gas constant and T is temperature.
From the question above, we know that
Pa = Pb = P
na = 3nb
Find the temperature of the cylinder a
P . V = n . R . Ta
Ta = P . V /( na . R )
Substitute na
Ta = P . V /( (3nb) . R )
Ta = (1/3) x (P . V /( (nb . R ))
Find the temperature of the cylinder b
P . V = n . R . Tb
Tb = P . V /( nb . R )
The cylinder a temperature is 3 times smaller than the temperature in cylinder b.
Find more on ideal gas at: brainly.com/question/25290815
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