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LenaWriter [7]
3 years ago
6

The perimeter of a rectangle is 66 feet. Find its dimensions assuming that its length is 9 feet less than twice its width.

Physics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:

Length = 19 feet

Width = 14 feet

Explanation:

The perimeter, P, of a rectangle is given by

P=2(l+w)

where l is the length and w is the width.

From the question, the length is 9 feet less than twice the width.

l=2w-9

Substitute this in the equation for the perimeter.

P=2(2w-9+w)

P=2(3w-9)

66=2(3w-9)

33=3(w-3)

11=w-3

w=14

Substitute for this in the equation for l.

l=2w-9=2\times14-9=28-9=19

Hence, the length is 19 feet and the width is 14 feet.

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A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and v
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Total displacement along the length of mountain is given as

L = 235 m

angle of mountain with horizontal = 35 degree

now we will have horizontal displacement as

x = L cos35

x = 235 cos35 = 192.5 m

similarly for vertical displacement we can say

y = L sin35

y = 235 sin35 = 134.8 m

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The gravitational pull between Pluto and the sun would be increased if
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pluto was closer

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Scientist A believes she has discovered a new procedure that is better than a procedure currently in use by physicians. She test
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A block of ice(m = 14.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal for
nadezda [96]

Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block (W), measured in newtons, is:

W = m\cdot g (1)

Where:

m - Mass of the block of ice, measured in kilograms.

g  - Gravitational acceleration, measured in meters per square second.

If we know that m = 14\,kg and g = 9.807\,\frac{m}{s^{2}}, the magnitudes of the weight and normal force of the block of ice are, respectively:

N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

N = W = 137.298\,N

And the pull force is:

F_{pull} = 98\,N

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f} (2)

Where:

v_{o}, v_{f} - Initial and final speeds of the block, measured in meters per second.

\Sigma F - Horizontal net force, measured in newtons.

\Delta t - Impact time, measured in seconds.

Now we clear the final speed in (2):

v_{f} = v_{o}+\frac{\Sigma F\cdot \Delta t}{m}

If we know that v_{o} = 0\,\frac{m}{s}, m = 14\,kg, \Sigma F = 98\,N and \Delta t = 1.40\,s, then final speed of the ice block is:

v_{f} = 0\,\frac{m}{s}+\frac{(98\,N)\cdot (1.40\,s)}{14\,kg}

v_{f} = 9.8\,\frac{m}{s}

The final speed of the block of ice is 9.8 meters per second.

6 0
3 years ago
5) Sally has a mass of 50 kg. She ran with a velocity of 20 m/s.
Ket [755]

Answer:

<h2>10,000 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2} \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 50 \times  {20}^{2}  \\  = 25 \times 400 \\  = 10000

We have the final answer as

<h3>10,000 J</h3>

Hope this helps you

7 0
2 years ago
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