According to the electromagnetic spectrum,
2 answers:
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Answer:
0.56
Explanation:
Let the coefficient of friction is μ.
m = 4.3 kg, θ = 30 degree, initial velocity, u = 0, s = 2.7 m, t = 5.8 s
By the free body diagram,
Normal reaction, N = mg Cosθ = 4.3 x 9.8 x Cos 30 = 36.49 N
Friction force, f = μ N = 36.49 μ
Net force acting on the block,
Fnet = mg Sinθ - f = 4.3 x 9.8 x Sin 30 - 36.49 μ
Fnet = 21.07 - 36.49μ
Net acceleartion, a = Fnet / m
a = (21.07 - 36.49μ) / 4.3
use second equation of motion
s = ut + 1/2 a t^2
2.7 = 0 + 1/2 x (21.07 - 36.49μ) x 5.8 x 5.8 / 4.3
By solving we get
μ = 0.56
Answer:
1) 57 revolutions.
2) 4.52 m
3) 1531.2 m
Explanation:
Question 1:
Given:
Initial velocity,
Final velocity,
Time,
Acceleration,
Now, displacement of the tire is given as:
Displacement of tire in 1 revolution is equal to its circumference.
Therefore, displacement in 1 revolution =
Now, number of revolutions is given as:
Therefore, the number of revolutions are 57.
Question 2:
Given:
Radius of the wheel is,
Angle of rotation is, °
Converting degree to radians, we get:
Now, path length is given as:
Therefore, the path length of a point on the wheel is 4.52 m
Question 3:
Radius of the wheel is,
Angle of rotation is, radians
Now, path length is given as:
Therefore, the path length of a point on the wheel is 1531.2 m.