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Pani-rosa [81]
3 years ago
11

According to the electromagnetic spectrum,

Physics
2 answers:
olga_2 [115]3 years ago
5 0
A. long-wave radiation occupies a smaller percentage than short-wave radiation
dezoksy [38]3 years ago
4 0
From the Electromagnetic Spectrum:

Radio, Micro wave, Infrared, Visible light, Ultra Violet, X rays, Y rays.

Only the Radio wave of wavelength 10³ m, has a positive power index, others have a negative exponent.

So these long waves form a smaller percentage.

Option A is correct. Others are not true. 
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Which object had more potential energy when it was lifted to a distance of 1000 centimeters? Show your calculation.
RSB [31]

Explanation:

We Know That

POTENTIAL ENERGY= MASS*g*HEIGHT

When the objects are lifted to same height then the object with heavier mass would have the highest potential energy

.

5 0
3 years ago
A group of tissues working together to perform a similar function.
inn [45]

Answer:

organ

Explanation:

7 0
4 years ago
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An Na ion has a charge of +1 and an O ion has a charge of –2. How many Na ions does one O ion need to balance charges
Aleonysh [2.5K]
Because Na⁺ ion lacks an electron and O²⁻ has two extra electrons extra, to balance the charge, we need 2 Na⁺ ions.
 
All ions, atoms and molecules want to get to the minimum energy state, and that state is when the ion, atom, or molecule is neutral, that's why all of them want to balance their charges. 
7 0
3 years ago
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12) Photosynthesis is a chemical reaction where carbon dioxide and water react to form glucose (C6H12O6) and oxygen gas. Which r
marusya05 [52]
6CO2 + 6H2O → C6H12O6 + 6O2
4 0
4 years ago
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You are comparing two diffraction gratings using two different lasers: a green laser and a red laser. You do these two experimen
Nikolay [14]

Answer:

a. (a) grating A has more lines/mm; (b) the first maximum less than 1 meter away from the center

Explanation:

Let  n₁ and n₂ be no of lines per unit length  of grating A and B respectively.

λ₁ and λ₂ be wave lengths of green and red respectively , D be distance of screen and d₁ and d₂ be distance between two slits of grating A and B ,

Distance of first maxima for green light

= λ₁ D/ d₁

Distance of first maxima for red light

= λ₂ D/ d₂

Given that

λ₁ D/ d₁ = λ₂ D/ d₂

λ₁ / d₁ = λ₂ / d₂

λ₁ / λ₂  = d₁ / d₂

But

λ₁  <  λ₂

d₁ < d₂

Therefore no of lines per unit length of grating A will be more because

no of lines per unit length  ∝ 1 / d

If grating B is illuminated with green light first maxima will be at distance

λ₁ D/ d₂

As λ₁ < λ₂

λ₁ D/ d₂ < λ₂ D/ d₂

λ₁ D/ d₂ < 1 m

In this case position of first maxima will be less than 1 meter.

Option a is correct .

5 0
3 years ago
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