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3 years ago

9

If Luke pushes his sister in a wagon down the driveway that is 14 meters long and it takes 22 Newton’s of force how much work di

d he do?

1 answer:

user100 [1]3 years ago

3 0

Answer:

308 J

Explanation:

The work done by a force applied parallel to a displacement is given by:

$W=Fd$

where

F is the magnitude of the applied force

d is the displacement

In this problem, we have

F = 22 N is the force applied

d = 14 m is the displacement of the wagon

Therefore, assuming that the force is parallel to the displacement, the work done is

$W=Fd=(22 N)(14 m)=308 J$

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An EM wave has a wave length of 956 m, What type of electromagnetic waves is this wave

Assoli18 [71]

The electromagnetic spectrum allows finding the result for the question of type of electromagnetic wave has a wavelength of 956 nm

The wave is in the near infrared range.

The electromagnetic wave is an oscillation of electric fields and magnets field that sustain each other, this wave time has the characteristics that it can travel without a material medium, for which they are of extreme importance.

Consequently the spectrum of electromagnetic waves to each part has been given a different name second to its use, for example

Range Name

Ultraviolet light 200 to 400 nm

Visible light 400 to 700 nm

Infrared light (heat ) 700 nm to 1 mm

The latter is subdivided into:

Near infrared 700 nm to 1000 nm (1 μm)

Medium infrared 1 μm to 30 μm

Far infrared 50 μm to 1000 μm

It indicates that the wavelength of the measured radiation is 956 nm, therefore it is in the near infrared range.

Learn more about the electromagnetism spectrum here: brainly.com/question/23727978

6 0

2 years ago

If 27 J of work are needed to stretch a spring from 15 cm to 21 cm and 45 J are needed to stretch it from 21 cm to 27 cm, what i

kupik [55]

Answer:

9 cm.

Explanation:

The energy used for stretch the spring from $15 cm$ to $21 cm$ will be , $E_{1}=27J$

The energy used for stretch the spring from $21 cm$ to $27 cm$ will be , $E_{2}=45J$

using the energy of spring formula ,we find that

$27 = \frac{1}{2}K((21-L^{2})-(15-L^{2}))$

$45 = \frac{1}{2}K((27-L^{2})-(21-L^{2}))$

Dividing both the equation will get,

$\frac{3}{5}=\frac{(21-L)^{2}-(15-L)^{2}}{(27-L)^{2}-(21-L)^{2}}\\5((21-L)^{2}-(15-L)^{2})=3((27-L)^{2}-(21-L)^{2})\\3(729 - 54L + L^{2}- 441 + 42L - L^{2} ) = 5(441 - 42L + L^{2} - 225 + 30L - L^{2} )\\3(288 - 12L) = 5(216 - 12L)\\24L = 216\\L = 9 cm$

Therefore, the natural length of the spring is, 9 cm.

4 0

2 years ago

a stone is thrown horizonttaly from a cliff of a hill with an initial velocity of 30m/s it hits the ground at a horizontal dista

ELEN [110]

Answer:

a) Time = 2.67 s

b) Height = 35.0 m

Explanation:

a) The time of flight can be found using the following equation:

$x_{f} = x_{0} + v_{0_{x}}t + \frac{1}{2}at^{2}$ (1)

Where:

$x_{f}$ : is the final position in the horizontal direction = 80 m

$x_{0}$ : is the initial position in the horizontal direction = 0

$v_{0_{x}}$ : is the initial velocity in the horizontal direction = 30 m/s

a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)

t: is the time =?

By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:

$t = \frac{x_{f}}{v_{0}} = \frac{80 m}{30 m/s} = 2.67 s$

b) The height of the hill is given by:

$y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}$

Where:

$y_{f}$ : is the final position in the vertical direction = 0

$y_{0}$ : is the initial position in the vertical direction =?

$v_{0_{y}}$ : is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)

g: is the acceleration due to gravity = 9.81 m/s²

Hence, the height of the hill is:

$y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m$

I hope it helps you!

5 0

2 years ago

Which single force acts on an object in free fall

ICE Princess25 [194]

Answer:

gravity

Explanation:

4 0

3 years ago

Read 2 more answers

In Paul Hewitt's book, he poses this question: "If the forces that act on a bullet and the recoiling gun from which it is fired

Sauron [17]

They have different accelerations because of their masses. According to Newton's Second Law, an objects acceleration is inversely proportional to its mass. Therefore the object with the larger mass, in this case the gun, will have a smaller acceleration. In the same way, the less massive object, being the bullet, will have a higher acceleration.

Hope this helps :)

4 0

3 years ago