Answer:
7500 m/s
Explanation:
We can use the equation velocity of a wave equals wavelength times frequency. Therefore, v = wavelength*f = (25 m)(300 Hz) = m/s7,500
To solve this problem we must simply resort to Newton's second law as well as the relationship between pressure and force as a physical unit applied in a given area.
In mathematical terms the Weight can be expressed as
Where,
m = mass
g = Gravitational Acceleration
We have the mass and the gravitational acceleration therefore the Weight is
Replacing we have
In this way the pressure exerted according to the active Area is,
Therefore the pressure difference between the lower and upper surface of the wings is 9.14kPa
Answer:
The elastic potential energy of the spring is 0.28 J
Explanation:
Given;
mass of the block, m = 0.05 kg
spring constant, k = 350 N/m
extension of the spring, x = 4 cm = 0.04 m
The elastic potential energy of the spring is calculated as;
Therefore, the elastic potential energy of the spring is 0.28 J
Answer:
I think the answer is b but i cannot confirm cuz this is a challenging question