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sammy [17]
3 years ago
5

A ball is thrown upward. The total time the ball remains in the air is 14 s. a) With what speed was the ball thrown upward? b) W

hat is the maximum height reached by the ball?
Physics
1 answer:
wolverine [178]3 years ago
5 0

Answer:

a) Vi = 137.2 m/s

b) h = 960.4 m

Explanation:

a)

In order to find the initial speed we will use first equation of motion:

Vf = Vi + gt

where,

Vf = Final velocity = 0 m/s (since ball stops at highest point)

Vi = Initial Velocity = ?

g = - 9.8 m/s² (negative sign for upward moyion)

t = time interval = 14 s

Therefore,

0 m/s = Vi + (-9.8 m/s²)(14 s)

<u>Vi = 137.2 m/s</u>

<u></u>

b)

Now, we use second equation of motion to find height (h):

h = Vi t + (1/2)gt²

h = (137.2 m/s)(14 s) + (1/2)(-9.8 m/s²)(14 s)²

h = 1920.8 m - 960.4 m

<u>h = 960.4 m</u>

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Answer:

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