(a) The magnitude of the acceleration of the electron is 5.62 x 10¹³ m/s².
(b) The speed of the electron after the given time is 4.78 x 10⁵ m/s.
<h3>
Acceleration of the electron</h3>
The acceleration of the electron is calculated as follows;
F = qE
ma = qE
a = qE/m
a = (1.6 x 10⁻¹⁹ x 320)/(9.11 x 10⁻³¹)
a = 5.62 x 10¹³ m/s²
<h3>Speed of the electron</h3>
v = at
v = 5.62 x 10¹³ m/s² x 8.50 x 10⁻⁹ s
v = 4.78 x 10⁵ m/s
Learn more about speed here: brainly.com/question/4931057
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thank you so much for the schlatt
Answer:
Explanation:
v = u +at
u = 0
a = 2.3 m /s²
t = 20 s
v = 2.3 x 20
= 46 m /s
Distance covered under acceleration of 2.3 m/s²
s = ut + 1/2 at²
= 0 + .5 x 2.3 x 20²
= 460 m
After that it moves under free fall ie g acts on it downwards .
v² = u² - 2gh , h is height moved by it under free fall
0 = 46² - 2 x 9.8 h
h = 107.96 m
Total height attained
= 460 + 107.96
= 567.96 m
b ) At its highest point ,it stops so its velocity = 0
c ) rocket's acceleration at its highest point = g = 9.8 downwards .
At highest point , it is undergoing free fall so its acceleration = g
To find out scientific notation, you want to make sure that number is less than 10. So do 5.000000, you don't rally need the zeros but I just want to make my point. So use 10^x meaning ten the whatever power adds zeros like 5.000000x10^6 meaning it is increasing it by six zeros moving it out of the decimals and letting become 5,000,000.
Answer:
a) x = 8.8 cm * cos (9.52 rad/s * t)
b) x = 8.45 cm
Explanation:
This is a Simple Harmonic Motion, and most Simple Harmonic Motion equations start from the equilibrium point. In this question however, we are starting from the max displacement the equations, and thus, it ought to be different.
From the question, we are given that
A = 8.8 cm = 0.088 m
t = 0.66 s
Now, we need to find the angular speed w, such that
w = 2π/T
w = (2 * 3.142) / 0.66
w = 6.284 / 0.66
w = 9.52 rad/s
The displacement equation of Simple Harmonic Motion is usually given as
x = A*sin(w*t)
But then, the equation starts from the equilibrium point at 0 sec, i.e x = 0 m
When you have to start from the max displacement, then the equation would be
x = A*cos(w*t).
So when t = 0 the cos(0) = 1, and then x = A which is max displacement.
Thus, the equation is
x = 8.8 cm * cos (9.52 rad/s * t)
At t = 1.7 s,
x = 8.8 cos (9.52 * 1.7)
x = 8.8 cos (16.184)
x = -8.45 cm
