The internal energy r<span>efers to the total energy of a system. The enrgies are kinetic energy and potential energy of the system that makes up the whole energies of the system.</span>
Explanation:
1)  + 7 H_2(g)](https://tex.z-dn.net/?f=%202%20Al%28s%29%20%2B%202%20NaOH%28aq%29%20%2B%206%20H_2O%28l%29%20%5Clongleftrightarrow%202%20Na%5BAl%28OH%29_4%5D%28aq%29%20%2B%207%20H_2%28g%29)
![Kc=\frac{[Na[Al(OH)_4]]^2*[H_2]^7}{[NaOH]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BNa%5BAl%28OH%29_4%5D%5D%5E2%2A%5BH_2%5D%5E7%7D%7B%5BNaOH%5D%5E2%7D)
The Kc for the reverse reaction is the inverse of the Kc of the reaction:

2) 
![Kc=\frac{[H_2SO_4]}{[SO_3]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2SO_4%5D%7D%7B%5BSO_3%5D%5E2%7D)
The Kc for the reverse reaction is the inverse of the Kc of the reaction:

3)
![Kc=\frac{1}{[O_2]^3}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B1%7D%7B%5BO_2%5D%5E3%7D)
The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Answer:
60.12 miles
Explanation:
Using the calculation formula shown below:
\frac{N_{o} }{N_{t} } }[/tex]
where:
is the half life,
is the original amount of F-18, and
is the remaining amount of F-18 at time t.
Generally, F-18 has an half life of 1.83 hours.
Therefore:
\frac{100}{68} = 1.02 hours[/tex]
Therefore using a speed of 59 miles/hour, the closeness of the hospital is:
distance = speed*time = 59*1.02 = 60.12 miles
N=N/Na
----. N=nxNa=3x6.023x10^23=<span>1.8069e+24</span>
Answer:
If you mean the number of atoms in 8g of oxygen, it's 3.011 x 10^23 atoms.
Explanation:
Convert the grams to moles. 8 grams of oxygen is 0.5 moles. Then multiply the number of moles by Avogadro's number: 6.022 x 10^23.