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slavikrds [6]
4 years ago
7

This chart shows what happens when each object is placed on a balance with a 10 kg weight on the other side.

Physics
2 answers:
kogti [31]4 years ago
7 0

Answer:

Balanced forces do not cause a change in motion. When balanced forces act on an object at rest, the object will not move. ... Forces that cause a change in the motion of an object are unbalanced forces. Unbalanced forces are not equal and opposite.

Explanation:

Any push or pull is a force. To describe a force, you must know two things. You must know the size of the force and the direction of the force. Suppose two teams are playing tug of war. Each team is pulling with equal force, but in opposite directions. Neither team can make the other team move. Forces that are equal in size but opposite in direction are called balanced forces.

tug of war balanced

Balanced forces do not cause a change in motion. When balanced forces act on an object at rest, the object will not move. If you push against a wall, the wall pushes back with an equal but opposite force. Neither you nor the wall will move. Forces that cause a change in the motion of an object are unbalanced forces.

tug of war unbalanced 1

Unbalanced forces are not equal and opposite. Suppose that one of the teams in tug of war pulls harder than the other team. The forces would no longer be equal. One team would be able to pull the other team in the direction of the larger force.

Force and Motion

More than one force can act on an object at the same time. If you hold a paper clip near a magnet, you, the magnet and gravity all exert forces on the paper clip. The combination of all the forces acting on an object is the net force. When more than one force is acting on an object, the net force determines the motion of the object. In this example, the paper clip is not moving, so the net force is zero.

How do forces combine to form the net force? If the forces are in the same direction, they add together to form the net force. Suppose you and a friend are asked to move a piano for the music teacher. To do this, you pull on one end of the piano, and your friend pushes on the other end. Together, your forces add up to enough force to move the piano. This is because your forces are in the same direction. Because the forces are in the same direction, they can be added together to determine the net force. In this case, the net force is 45 N, which is plenty to move a piano - if it is on wheels, that is!

net force piano

If two forces are in opposite directions, then the net force is the difference between the two forces, and it is in the direction of the larger force. Consider two dogs playing tug of war with a short piece of rope. Each is exerting a force, but in opposite directions.

Notice below that the dog on the left is pulling with a force of 10 N, and the dog on the right is pulling with a force of 12 N. Which dog do you think will win the tug of war? Because the forces are in opposite directions, the net force is determined by subtracting the smaller force from the larger one. In this case, the net force is 2 N in the direction of the dog on the right. Give that dog a dog biscuit!

Harman [31]4 years ago
7 0

Answer:

Object 1 is the heaviest

Explanation:

its right

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At a certain instant, a ball is thrown downward with a velocity of 8.0 m/s from a height of 40 m. At the same instant, another b
maks197457 [2]

Answer:

(a) The two balls collide 2\; \rm s after launch.

(b) The height of the collision is 4\; \rm m.

(Assuming that air resistance is negligible.)

Explanation:

Let vector quantities (displacements, velocities, acceleration, etc.) that point upward be positive. Conversely, let vector quantities that point downward be negative.

The gravitational acceleration of the earth points dowards (towards the ground.) Therefore, the sign of g should be negative. The question states that the magnitude of g\! is 10\; \rm m \cdot s^{-2}. Hence, the signed value of \! g should be \left(-10\; \rm m \cdot s^{-2}\right).

Similarly, the initial velocity of the ball thrown downwards should also be negative: \left(-8.0\; \rm m \cdot s^{-1}\right).

On the other hand, the initial velocity of the ball thrown upwards should be positive: \left(12\; \rm m \cdot s^{-1}\right).

Let v_0 and h_0 denote the initial velocity and height of one such ball. The following SUVAT equation gives the height of that ball at time t:

\displaystyle h(t) = \frac{1}{2}\, g \cdot {t}^{2} + v_0 \cdot t + h_0.

For both balls, g = \left(-10\; \rm m \cdot s^{-2}\right).

For the ball thrown downwards:

  • Initial velocity: v_0 = \left(-8.0\; \rm m \cdot s^{-1}\right).
  • Initial height: h_0 = 40\; \rm m.

\displaystyle  h(t) = -5\, t^{2} + (-8.0)\, t + 40 (where h is in meters and t is in seconds.)

Similarly, for the ball thrown upwards:

  • Initial velocity: v_0 = \left(12\; \rm m \cdot s^{-1}\right).
  • Initial height: h_0 = 0\; \rm m.

\displaystyle  h(t) = -5\, t^{2} + 12\, t (where h is in meters and t is in seconds.)

Equate the two expressions and solve for t:

-5\, t^{2} + (-8.0)\, t + 40 = -5\, t^{2} + 12\, t.

t = 2.

Therefore, the collision takes place 2\, \rm s after launch.

Substitute t = 2 into either of the two original expressions to find the height of collision:

h = -5\times 2^{2} + 12 \times 2 = 4\; \rm m.

In other words, the two balls collide when their height was 4\; \rm m.

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An object measures 7.32 cm by 2.14 cm by 3.21 cm and the mass is 7.89 g. Calculate the<br> density.
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Explanation:

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A truck is parked at the bottom of a hill. It moves from the bottom of a hill
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Answer:

C

Explanation:

potential energy is stored energy that an object has due to its position or chemical composition. Since the truck has the possibility to move down the hill when it is at the top of the hill, it has a great amount of potential energy, howver when its at the bottom of the hill, it doesn’t have the possibility to move or can move v little due to its positions,  therefore it has little to no potienatal energy.

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Which of the following best describes the function of a resistor in an electrical circuit?
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Answer:

It controls the amount of current.

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A resistor helps control and maintain the circuit which is it's main function.

8 0
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It takes 15 min to drive 6.0 mi in a straight line to the local hospital. It takes 10 min to go the last 3.0 mi, 2.0 min to go t
Gala2k [10]

Answer:

36.87 km/h

Explanation:

Convert all the units in SI system

1 mile = 1609.34 m

d1 = 6 mi = 9656.04 m

t1 = 15 min = 15 x 60 = 900 s

d2 = 3 mi = 4828.02 m

t2 = 10 min = 10 x 60 = 600 s

d3 = 1 mi = 1609.34 m

t3 = 2 min = 2 x 60 = 120 s

d4 = 0.5 mi = 804.67 m

t4 = 0.5 min = 0.5 x 60 = 30 s

Total distance, d = d1 + d2 + d3 + d4

d = 9656.04 + 4828.02 +  1609.34 + 804.67 = 16898.07 m = 16.898 km

total time, t = t1 + t2 + t3 + t4

t = 900 + 600 + 120 + 30 = 1650 s = 0.4583 h

The ratio of the total distance covered to the total time taken is called average speed.

Average speed = 16.898 / 0.4583 = 36.87 km/h

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