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MAVERICK [17]
3 years ago
11

A 50-kilogram student is running and has 225 joules of kinetic energy.What is the students speed in meters per second

Physics
2 answers:
lord [1]3 years ago
7 0

Answer:

3 m/s

Explanation:

Andreas93 [3]3 years ago
6 0

Answer:3m/s

Explanation:

mass(m)=50kg

Kinetic energy =225 joules

Kinetic energy=(m x (velocity)^2)/2

225=(50 x (velocity)^2)/2

Cross multiplying we get

225x2=50x(velocity)^2

450=50x(velocity)^2

Divide both sides by 50

450/50=(50x(velocity)^2)/50

9=(velocity)^2

Taking the square root of both sides we get

√9=velocity

3=velocity

Velocity=3m/s

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A small balloon is released at a point 150 feet away from an observer, who is on level ground. If the balloon goes straight up a
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\dfrac{dz}{dt}=0.65\ ft/s

Explanation:

Given that

x= 150 ft

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From the diagram

z^2=x^2+y^2

When ,x= 150 ft and y= 14 ft

z^2=150^2+14^2

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z=150.74 ft

z^2=x^2+y^2

By differentiating with respect to time t

2z\dfrac{dz}{dt}= 2x\dfrac{dx}{dt}+2y\dfrac{dy}{dt}

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Here x is constant that is why

\dfrac{dx}{dt}=0

z\dfrac{dz}{dt}= y\dfrac{dy}{dt}

Now by putting the values in the above equation we get

150.74\times \dfrac{dz}{dt}=14\times 7

\dfrac{dz}{dt}=\dfrac{14\times 7}{150.74}\ ft/s

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Therefore the distance between balloon and observer increasing with 0.65 ft/s.

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A uniform rod of length L, mass M, is suspended by two thin strings. Which of the following statements is true
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