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gayaneshka [121]
3 years ago
7

The eccentricity of an asteroid's orbit is 0.0442, and the semimajor axis is 1.12 x 1011 m. The Sun's center is at one focus of

the asteroid's orbit. (a) How far from this focus is the other focus in meters? (b) What is the ratio of this distance to the solar radius, 6.96 x 108 m?
Physics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

a. d=99x10^{8}m

b. r=14.22 R_s

Explanation:

The eccentricity of an asteroid's is 0.0442 so

a.

to find the focus distance between both focus is

d=2*e*a

e=1.12x10^{11}m\\a=0.0442

So replacing numeric

d=2*1.12x10^{11}m*0.0442=9900800000

d=99x10^{8}m

b.

Now to find the ratio of that distance between the solar radius and the distance

r=\frac{d_1}{d_s}

r=R_s*\frac{99x10^8m}{6.96x10^8m}

r=14.22 R_s

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If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?
vovikov84 [41]

Complete Question

In an action movie, the villain is rescued from the ocean by grabbing onto the ladder hanging from a helicopter. He is so intent on gripping the ladder that he lets go of his briefcase of counterfeit money when he is 130 m above the water. If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?

Answer:

The speed of the helicopter is u  =  7.73 \  m/s

Explanation:

From the question we are told that

   The height at which he let go of the brief case is  h =  130 m  

    The  time taken before the the brief case hits the water is  t =  6 s

Generally the initial speed of the  briefcase (Which also the speed of the helicopter )before the man let go of it is  mathematically evaluated using kinematic equation as

      s = h+  u t +  0.5 gt^2

Here s  is the distance covered by the bag at sea level which is zero

      0 = 130+  u * (6) +  0.5  *  (-9.8) * (6)^2

=>    0 = 130+  u * (6) +  0.5  *  (-9.8) * (6)^2

=>   u  =  \frac{-130 +  (0.5 * 9.8 *  6^2) }{6}

=>   u  =  7.73 \  m/s

     

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In operant conditioning, generalization occurs when
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4 years ago
Read 2 more answers
If a clock expends 2 W of power from a 1.5 V battery what amount of current is supplying the clock?
wolverine [178]
1.3 A
If a clock expends 2 W of power from a 1.5 V battery, what amount of current is supplying
the clock?
solution
as we know
p=vi
i=p/v
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=1.3A
7 0
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