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skad [1K]
2 years ago
12

Which of the following is an inner transition element?

Chemistry
1 answer:
KiRa [710]2 years ago
4 0

Option E) Th is correct answer. Thorium (Th) is inner transition element.

  • The components that make up the f-block are those where the 4f and 5f orbitals gradually fill up.
  • Although they are officially members of group 3, these elements are displayed separately in the f-block of the periodic table. Inner transition elements are another name for the f-constituent block's parts.
  • Lanthanoids and actinoids are the names for the two series of inner transition elements that are 4f and 5f series, respectively.
  • The inner transition elements U, Th, and Pa are excellent nuclear energy sources.
  • The inner transition elements' electronic configuration is 4f1-14 5d0-16 s².
  • Due to their uniform size and outer shell design, elements in a series would all have comparable qualities, making it difficult to distinguish them from one another.

Hence, thorium is inner transition element.

Learn more about lanthanoids here:

brainly.com/question/13760918

#SPJ9

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Aluminum has a density of 2.70 g/mL. A sample of aluminum weighs 67.5 g. If this sample is put into a graduated cylinder that ha
romanna [79]

Answer:

60 ml

Explanation:

Now, we know that density = mass/volume

Mass of aluminium = 67.5 g

volume of aluminium =?

density of aluminium = 2.70 g/mL

volume of aluminium = mass/density = 67.5/2.70 = 25 ml

Since volume of water in the cylinder = 35 ml

The water rises to ; 35 ml + 25 ml = 60 ml

4 0
3 years ago
A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a
Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = m C .ΔT

m is mass of the solution = 151.8 mL * \frac{1 g}{1 mL} = 151.8 g

C is the specific heat of solution = 4.18 \frac{J}{g. ^{0}C}

ΔT is the temperature change = 31.50^{0}C - 21.45^{0}C = 10.05^{0}C

q = 151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J

Moles of NaOH = 101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol NaOH

Moles of H_{2}SO_{4} = 50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}

Enthalpy of the reaction = \frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol

5 0
3 years ago
How many electrons are present in 4He2+?
Charra [1.4K]
4 and 2 electrons are present.
4 0
3 years ago
What unusual thing can the bull shark do?
kotegsom [21]
Bull sharks have the unique ability of keeping salt in their bodies even freshwater
3 0
3 years ago
If 26.2 grams of a pure compound contain 8.77 × 1022 molecules, what is the molecular weight of this compound? Answer in units o
Nataly [62]

Answer:

Mw = 179.845 g/mol

Explanation:

  • Mw [=] g/mol

∴ w = 26.2 g

∴ 1 mol = 6.02 E23 molecules.......Avogadro's number

⇒N° moles = 8.77 E22 molecules * ( mol / 6.02 E23 molecules ) = 0.146 mol

⇒ Mw = 26.2 g / 0.146 mol = 179.845 g/mol

3 0
3 years ago
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