I think the answer is d not real fir sure I'll find out in the morning sorry
Answer:
The correct option is;
Placing one drop of food coloring in a cup with 60 ml of water at 10°, placing one drop of food coloring in a second cup with 60 ml of water at 40°C
Explanation:
The experimental setup that would allow the student investigate the connection between kinetic energy and temperature should be made up of the following characteristics
1) The constant terms for the experiment should be defined, which in this case are
a) The volume of the water which is 60 ml in both subjects of the experiment
2) The definition of the variable that produces the effect that is being monitored, which is the use of the different temperatures in the two experimental subjects
3)The environmental limits of the experiment, which is the water and the food coloring used
The balanced chemical equation for the combustion of butane is:
Δ
= Σ
Δ
-Σ
Δ
= ![[{8*(-393.5kJ/mol)}+{10*(-241.82kJ/mol)}]-[{2*(-125.6kJ/mol)}+13*(0 kJ/mol)}]](https://tex.z-dn.net/?f=%5B%7B8%2A%28-393.5kJ%2Fmol%29%7D%2B%7B10%2A%28-241.82kJ%2Fmol%29%7D%5D-%5B%7B2%2A%28-125.6kJ%2Fmol%29%7D%2B13%2A%280%20kJ%2Fmol%29%7D%5D)
=[-3148kJ/mol+(-2418.2kJ/mol)]-[(-251.2kJ/mol)+0]
= -5315 kJ/mol
Calculating the enthalpy of combustion per mole of butane:
Therefore the heat of combustion per one mole butane is -2657.5 kJ/mol
Correct answer: -2657.5 kJ/mol
Answer:
The number of chlorine atoms present in 
units of gold III chloride is 
Explanation:
Formula of Gold (III) chloride: 
<em>Avogadro Number</em> : Number of particles present in <u>one mole</u><u> </u>of a substance.
Using,
= 1 mole(0.9999 , nearly equal to 1 )
The given Gold III chloride sample is 1 mole in amount.
= 1 mole of
In this Sample,
1 mole of will give = 3 mole of Chlorine atoms
1 mole of Cl contain =
3 mole of Cl contain = 
3 mole of Cl contain =
So,
The number of chlorine atoms present in units of gold III chloride is
Answer:
f = 1.1041 × 10¹⁵ s⁻¹
λ = 2.72 × 10⁻⁷ m
Explanation:
Given data:
Energy of photon = 7.32 × 10⁻¹⁹ J
Wavelength = ?
Frequency = ?
Solution:
Formula
E = h. f
h = planck's constant = 6.63 × 10⁻³⁴ Kg.m²/s
Now we will put the values in equation
f = E/h
Kg.m²/s² = j
f = 7.32 × 10⁻¹⁹ Kg.m²/s² / 6.63 × 10⁻³⁴ Kg.m²/s
f = 1.1041 × 10¹⁵ s⁻¹
Wavelength of photon.
E = h.c /λ
λ = h. c / E
λ = (6.63 × 10⁻³⁴ Kg.m²/s × 3 × 10⁸ m/s) / 7.32 × 10⁻¹⁹ Kg.m²/s²
λ = 19.89 × 10⁻²⁶ / 7.32 × 10⁻¹⁹ m
λ = 2.72 × 10⁻⁷ m
