Answer:
a) Ф = 0
b) P_avg=2*P_avg,1
Explanation:
<u>Givens:</u>
The phase difference is 0, 0.2λ, or 0.5λ between the waves.
<u>Part a: </u>
since the amplitude of the wave is directly proportional to the average rate so that the waves will transport greater energy when Ф = 0
Part b:
The two waves are identical to the first wave, the net amplitude is twice the first waves and the travel in the same tube thus
P_avg=2*P_avg,1
Answer:
- the speed of a person "stuck" to the wall is 14.8 m/s
- the normal force of the wall on a rider of m=54kg is 1851 N
- the minimum coefficient of friction needed between the wall and the person is 0.29
Explanation:
Given information:
the radius of the cylindrical room, R = 6.4 m
the room spin with frequency, ω = 22.1 rev/minutes = 22.1
= 2.31 rad/s
mass of rider, m = 54 kg
the speed of a person "stuck" to the wall
v = ω R
= 2.31 x 6.4
= 14.8 m/s
the normal force of the wall on a rider
F = m a
a = ω^2 R
=
R
= 
F = 
= 
= 1851 N
the minimum coefficient of friction needed between the wall and the person
F(friction) = μ N
W = μ N
m g = μ 
g = μ
μ = 
= 
= 0.29
The type of torque wrench designed for tightening clamping bands on underground pipe is the …No-Hub..
Answer:
Nima and Natasha are absolutely correct.
Explanation:
When connecting two resistors in series, their resistances add:

which means that whenever we add a resistance in series, their magnitudes will add, giving us a resistance that is greater than the original resistance, which will demand less current from the battery because of ohm's law:

So, the greater the resistance, the smaller the current.
When connecting two resistors in parallel, the reciprocal of ther resistances add:

or

The equivalent resistance will always be less than the smallest resistor in the circuit, so the equivalent resistance will always decrease as more resistors are added. A decrease in the resistance means that the current will increase.
When two atoms of the same nonmetal react,they form what we know today as a diatomic molecule.
Please mark brainliest. :)