Answer:
![[PCl_3]=[Cl_2]=0.068M](https://tex.z-dn.net/?f=%5BPCl_3%5D%3D%5BCl_2%5D%3D0.068M)
![[PCl_5]=0.385M](https://tex.z-dn.net/?f=%5BPCl_5%5D%3D0.385M)
Explanation:
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In this case, since the equilibrium expression for the considered equation is:
![Kc=\frac{[PCl_5]}{[Cl_2][PCl_3]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BPCl_5%5D%7D%7B%5BCl_2%5D%5BPCl_3%5D%7D)
Which can be written in terms of the reaction extent and the ICE chart and the initial concentrations of 0.453 M as shown below:

We can solve for x as follows:

In such a way, we obtain the following concentrations at equilibrium:
![[PCl_3]=[Cl_2]=0.453M-0.385M=0.068M](https://tex.z-dn.net/?f=%5BPCl_3%5D%3D%5BCl_2%5D%3D0.453M-0.385M%3D0.068M)
![[PCl_5]=0.385M](https://tex.z-dn.net/?f=%5BPCl_5%5D%3D0.385M)
Best regards!
Refer to the table below. Credits to https://terpconnect.umd.edu/~wbreslyn/chemistry/naming/IonicCharge2.jpg
Cations with (+ ) charges lose electrons in order to obtain an octet (8 valence electrons) when they ionically bond with another ion. We're looking for the ions that loses electrons here. So, from the table:
Al 3+ , S 2- , O 2-, Ag + , Ne ( noble gas, no charge)
Since Al and Ag has (+) charges, they are going to lose electrons to form ionic bonds with other atoms.
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The percentage yield obtained from the given reaction above is 74.8%
<h3>Balanced equation </h3>
P₄ + 6Cl₂ → 4PCl₃
Molar mass of P₄ = 31 × 4 = 124 g/mol
Mass of P₄ from the balanced equation = 1 × 124 = 124 g
Molar mass of PCl₃ = 31 + (35.5×3) = 137.5 g/mol
Mass of PCl₃ from the balanced equation = 4 × 137.5 = 550 g
<h3>SUMMARY</h3>
From the balanced equation above,
124 g of P₄ reacted to produce 550 g of PCl₃
<h3>How to determine the theoretical yield </h3>
From the balanced equation above,
124 g of P₄ reacted to produce 550 g of PCl₃
Therefore,
79.12 g of P₄ will react to produce = (79.12 × 550) / 124 = 350.9 g of PCl₃
<h3>How to determine the percentage yield </h3>
- Actual yield of PCl₃ = 262.6 g
- Theoretical yield of PCl₃ = 350.9 g
Percentage yield = (Actual /Theoretical) × 100
Percentage yield = (262.6 / 350.9) × 100
Percentage yield = 74.8%
Learn more about stoichiometry:
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