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timurjin [86]
2 years ago
13

Ethyl (r)-4-phenylhexanoate was treated with ethyl lithium followed by acid hydrolysis (to neutralize). How many stereoisomers o

f the resulting alcohol were formed?
Chemistry
1 answer:
Oksanka [162]2 years ago
4 0

3 stereoisomers of the resulting alcohol were formed when Ethyl (r)-4-phenylhexanoate was treated with ethyl lithium followed by acid hydrolysis (to neutralize).

<h3>Stereoisomers:</h3>

In contrast to atomic connection, stereoisomers differ in the spatial arrangement of their atoms. The mirror-image stereoisomers, a non-superimposable pair of two molecules that are mirror images of one another, are one of their most intriguing types of isomers.

These include non-enantiomeric optical isomers, cis-trans isomers, E-Z isomers, and meso compounds. Rarely do diastereomers share the same physical characteristics. Stereoisomers are isomers that share the same structure (i.e., the same pieces), but differ in how those parts are arranged in space.

Stereoisomers are isomers that share the same structure (i.e., the same pieces), but differ in how those parts are arranged in space.

Learn more about stereoisomers here:

brainly.com/question/18120547

#SPJ4

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How many moles of copper are present in 75.0g Cu? Show your complete calculation and give the answer in the correct number of si
velikii [3]

Answer:

The answer to your question is 1.2 moles of copper

Explanation:

Data

mass of copper = 75 g

moles = ?

Process

1.- Look in the periodic table for the atomic mass of copper.

Atomic mass = 63.55 g/mol

2.- Use proportions to determine the moles of copper in 75 g

                          63.55 g of copper -------------------- 1 mol

                          75 g of copper       --------------------  x

Use cross multiplication

                          x = (75 x 1) / 63.55

                          x = 75 / 63.55

                          x = 1.18 moles ≈ 1.2 moles of copper

3 0
4 years ago
Read 2 more answers
Calculate the percent ionization of nitrous acid in a solution that is 0.222 M in nitrous acid (HNO3) and 0.278 M in potassium n
RideAnS [48]

Explanation:

Concentration of KNO_{2} is 0.278 M and it is completely ionized into K^{+} and NO^{-}_{2}.

This means that [KNO_{2}] = [NO_{2}] = 0.278 M

It is given that concentration of HNO_{2} is 0.222 M.

As HNO_{2} is a weak acid. Therefore, its dissociation will be as follows.

              HNO_{2}(aq) \rightarrow H^{+}(aq) + NO^{-}_{2}(aq)

Initially :    0.222 M            0        0.278 M

Change :    - x                    +x           +x

Equilibrium : 0.222 M - x    x         0.278 M + x

Therefore, dissociation constant for this reaction will be as follows.

        K_{a} = \frac{[H^{+}][NO^{-}_{2}]}{[HNO_{2}]}

Hence, putting the given values into the above formula as follows.

        K_{a} = \frac{[H^{+}][NO^{-}_{2}]}{[HNO_{2}]}

      4.50 \times 10^{-4} = \frac{x \times (0.278 + x)}{(0.222 - x)}

                          x = 0.00036

As, [H^{+}] is 0.00036 M. Therefore, percentage ionization of HNO_{2} will be calculated as follows.

              % ionization of HNO_{2} = \frac{[H^{+}]}{[HNO_{2}]} \times 100

                               = \frac{0.00036 M}{0.222 M} \times 100

                               = 0.16 %

Thus, we can conclude that % ionization of HNO_{2} is 0.16%.

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4 years ago
P4O10 + H2O —&gt; <br> what are the products
liubo4ka [24]

Answer:

P4O10 + H2O → H3PO4

Explanation:

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Which of the alkaline-earth metals has the smallest ionization energy?
gulaghasi [49]

Answer:

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Explanation:

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3 years ago
PLEASE help! BRAINLIEST to correct answer!
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Answer:

C

Explanation:

5 0
3 years ago
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