I’m not sure bro but I think the answer is D I’m like 80% sure if it’s right
Answer:
First, let's express pressure P in Pa and volume V in m3:
⇒P=175 kPa
⇒P=1.75×105 Pa
and
⇒V=275 ml
⇒V=2.75×10−4 m3
Then, let's solve the ideal gas law PV=nRT for temperature T:
⇒PV=nRT
⇒T=PVnR
Substituting the appropriate values into the equation:
⇒T=1.75×105×2.75×10−40.80×8.314 K
⇒T=48.1256.6512 K
∴T≈7.24 K
Therefore, the temperature is around 7.24 K.
B).Proton acceptor did that help at all
Letter A would sound about right.
For an element whose third shell contains six electrons, the appropriate electron configuration is; 1s2 2s2 2p6 3s2 3p4.
The electron configuration shows the distribution of electrons in the shells of an atom and in orbitals.
We have been told that the six electrons are found in the third shell. This shell has n=3 and the configuration of this shell must ns2 np4.
The only electron configuration that meets this standard is 1s2 2s2 2p6 3s2 3p4.
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