All categories

3 years ago

In the oxidation reduction reaction 2FeCl2 + Cl2 = 2FeCl3 what substance is reduced? What substance is oxidized?

Chemistry

1 answer:

marishachu [46]3 years ago

4 0

Answer:

Iron is oxidized while chlorine is reduced.

Explanation:

The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reaction:

2FeCl₂ + Cl₂ → 2FeCl₃

in this reaction the oxidation state of iron is increased from +2 to +3. That's why iron get oxidized and it is reducing agent because it reduced the chlorine. The chlorine is reduced from -2 to -3 and it is oxidizing agent because it oxidized the iron.

2Fe⁺²Cl₂⁻²

2Fe⁺³Cl₃⁻³

The iron atom gives it three electrons to three atoms of chlorine and gain positive charge while chlorine atom accept the electron and form anion.

You might be interested in

A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 64.0 mL of 0.0600 M EDTA . Titration of the excess unreacted EDTA req

tigry1 [53]

Answer:

the concentration of $Cd^{2+}$ in the original solution= 0.0088 M

the concentration of $Mn^{2+}$ in the original solution = 0.058 M

Explanation:

Given that:

The volume of the sample containing Cd2+ and Mn2+ = 50.0 mL; &

was treated with 64.0 mL of 0.0600 M EDTA

Titration of the excess unreacted EDTA required 16.1 mL of 0.0310 M Ca2+

i.e the strength of the Ca2+ = 0.0310 M

Titration of the newly freed EDTA required 14.2 mL of 0.0310 M Ca2+

To determine the concentrations of Cd2+ and Mn2+ in the original solution; we have the following :

Volume of newly freed EDTA = $\frac{Volume\ of \ Ca^{2+}* Sample \ of \ strength }{Strength \ of EDTA}$

= $\frac{14.2*0.0310}{0.0600}$

= 7.3367 mL

concentration of $Cd^{2+}$ = $\frac{volume \ of \ newly \ freed \ EDTA * strength \ of \ EDTA }{volume \ of \ sample}$

= $\frac{7.3367*0.0600}{50}$

= 0.0088 M

Thus the concentration of $Cd^{2+}$ in the original solution = 0.0088 M

Volume of excess unreacted EDTA = $\frac{volume \ of \ Ca^{2+} \ * strength \ of Ca^{2+} }{Strength \ of \ EDTA}$

= $\frac{16.1*0.0310}{0.0600}$

= 8.318 mL

Volume of EDTA required for sample containing $Cd^{2+}$ and $Mn^{2+}$ = (64.0 - 8.318) mL

= 55.682 mL

Volume of EDTA required for $Mn^{2+}$ = Volume of EDTA required for

sample containing $Cd^{2+}$ and

$Mn^{2+}$ -- Volume of newly freed EDTA

Volume of EDTA required for $Mn^{2+}$ = 55.682 - 7.3367

= 48.3453 mL

Concentration of $Mn^{2+}$ = $\frac{Volume \ of EDTA \ required \ for Mn^{2+} * strength \ of \ EDTA}{volume \ of \ sample}$

Concentration of $Mn^{2+}$ = $\frac{48.3453*0.0600}{50}$

Concentration of $Mn^{2+}$ in the original solution= 0.058 M

Thus the concentration of $Mn^{2+}$ = 0.058 M

6 0

3 years ago

How does producers get matter?

Margaret [11]

A producer gets it's matter from it's surroundings. E.g a plant will get minerals and water from the ground through it's roots for photosynthesis.
Plants can also produce food by using the sun's light for photolysis of the water molecules. (Basically splitting the H20 into Hydrogen and O2 (oxygen gas). They release oxygen back into the air and combine the Hydrogen ion with carbon dioxide that they obtained from the air to create sugar (glucose) which is basically chemical food for the plants. This is the summed up process of photosynthesis.

6 0

3 years ago

If an atom has more protons than an electron, its net charge will be

Ierofanga [76]

Answer: If an object has more protons than electrons, then the net charge on the object is positive. If there are more electrons than protons, then the net charge on the object is negative. If there are equal numbers of protons and electrons, then the object is electrically neutral.

Explanation:

3 0

3 years ago

Read 2 more answers

The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleane

svet-max [94.6K]

Answer:

Explanation:

The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleaned from the third postulate in Dalton's series. Magnesium oxide decomposes into magnesium and oxygen. If 4.03 g of magnesium oxide decomposes to form 2.43 g of magnesium, what mass of oxygen gas is also released in the reaction

The word say magnesium oxide decomposes to magnesium and oxygen

the chemical symbols say

MgO-----------> Mg + O2 (since natural oxygen is diatomic)

the balanced equation says

2MgO-------------->2Mg + O2

4.03 gm----------> 2.43 + ?0 gms

tour high school Algebra I class says

? = 4.03 -2.43 =1.60

your chemical analytcal lab says %mO in MgO = 16/40.3 = 39.7%

your calculator says

39.7/100 X 4.03 = 1.60

all of these prove the law of conservation of mass

3 0

3 years ago

Copper(II) fluoride contains 37.42% F by mass. Calculate the mass of fluorine (in g) in 55.5 g of copper(II) fluoride.

Mrac [35]

Answer:

There are 20.8 g of fluorine in 55.5 g of copper (II) fluoride

Explanation:

x % by mass of a species in a specimen means there are x g of the species in total 100 g of a specimen

37.42 % F by mass means 100 g of copper (II) fluoride contains 37.42 g of F.

So, 100 g of copper (II) fluoride contains 37.42 g of F

55.5 g of copper (II) fluoride contains $\frac{37.42\times 55.5}{100}$ g of F or 20.8 g of F

Hence there are 20.8 g of fluorine in 55.5 g of copper (II) fluoride.

5 0

3 years ago