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iogann1982 [59]
4 years ago
10

Describe an application where a parallel circuit might work better than a series circuit

Physics
1 answer:
babunello [35]4 years ago
7 0
In rooms where there are multiple lights, a parallel circuit is better.

In a series circuit, if one light broke, all of the lights would turn off, as the circuit would be broken.

However, in parallel, if one bulb broke, the circuit could still be complete through the other bulbs, so they will stay on.
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If a resistor draws 1.2 x 10^-3 a of current from a 12 v battery, then what is the value of the resistor?
bixtya [17]
Value of resistor = (12V) /(1.2 x 10^-3A)=10000ohms=10k ohms
8 0
4 years ago
Which image best illustrates diffraction?
Stells [14]
Where’s the image?? i don’t see it
7 0
3 years ago
There is a distinction between average speed and the magnitude of average velocity. Give an example that illustrates the differe
Usimov [2.4K]

An example that illustrates the difference is the circular motion

Explanation:

Let's start by reminding the definition of the two quantities:

- Speed is a scalar quantity that tells "how fast" an object is moving, regardless of its direction of motion.

Speed can be  calculate as:

speed = \frac{d}{t}

where:

d is the distance travelled

t is the time taken

- Velocity is instead a vector quantity, given by:

velocity = \frac{d}{t}

where;

d is the displacement of the object (displacement is a a vector connecting the initial position to the final position of motion)

t is the time taken

Since it is a vector, velocity has both a magnitude and a direction, therefore it also takes into account the direction of motion of the object.

For an object in motion in a straight line, speed and velocity are the same. However, this is not always the case.

In fact, an example of motion in which the two quantities are different is the circular motion. Consider for example the object making one complete revolution along the circle. Therefore, its average speed is the ratio between the length of the perimeter (the distance) divided by the time taken:

speed = \frac{2\pi r}{t}

where r is the radius of the circle.

However, the displacement of the object is zero (because the object returns to the starting point), and so the average velocity is also zero:

velocity = \frac{0}{t}=0

Learn more about speed and velocity:

brainly.com/question/8893949

brainly.com/question/5063905

brainly.com/question/5248528

#LearnwithBrainly

5 0
3 years ago
In the first video for chapter 29, we looked at the emission spectrum of excited gases. In this video, we look at the __________
Elan Coil [88]

Although the video is not found here, the sentence makes reference to the transmission spectrum of colored filters.

<h3>What is the transmission spectrum?</h3>

The transmission spectrum indicates the light portion having a given wavelength that can be passed through a filter.

This spectrum (transmission spectrum) depends on the physical separation of the particles that form the filter.

In conclusion, although the video is not found here, the sentence makes reference to the transmission spectrum of colored filters.

Learn more about the transmission spectrum here:

brainly.com/question/1287536

#SPJ1

6 0
3 years ago
A long solenoid with 8.22 turns/cm and a radius of 7.00 cm carries a current of 19.4 mA. A current of 3.59 A exists in a straigh
daser333 [38]

Answer:

a. 3.039cm

b.magnetic field is B=2.958\times10^{-5}T

Explanation:

Direction of the solenoid magnetic field is along the axis of the solenoid. and magnetic field due to the wire perpendicular to that due to the solenoid.. Magnetic field at r is given by:

\overrightarrow B = \overrightarrow B_s+ \overrightarrow B_w,\ \ \ \ \  \overrightarrow B_s\perp \overrightarrow B_w

Angle of net magnetic field from axial direction is given by:

tan\  \theta=\frac{B_w}{B_s},

Field due to solenoid:

B_s=\mu_onI_s,  \ \ \ \ n=(8.22 t/cm)(100cm/m)=822turn/m

Field due to wire:

B_w=\frac{\mu_oI_w}{2\pi r}

Therefore, r:

tan\  \theta=\frac{B_w}{B_s}\\\\=\frac{\mu_oI_w}{2\pi r(\mu_o nI_s)}\\\\r=\frac{I_w}{2\pi  nI_stan \ \theta}\\\\r=\frac{3.59A}{2\pi\times822\times19.4\times10^{-3}A \ tan 49.7\textdegree}\\\\r=3.039cm

Hence, the radial distance is 3.039cm

b.The magnetic field strength is given by:

B=\sqrt{B_w^2+B_s^2}\\\\tan 49.7\textdegree=\frac{B_w}{B_s}\\\\1.179=\frac{B_w}{B_s}\\\\B_w=1.179B_s\\\\B=\sqrt{(4\pi\times10^{-7}T.m/A\times 822\times19.4\times10^{3}A)+1.179(4\pi\times10^{-7}T.m/A\times 822\times19.4\times10^{-3}A)}\\\\B=2.958\times10^{-5}T

Hence, the magnetic field is B=2.958\times10^{-5}T

7 0
4 years ago
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